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您好，我在集成支付网关时遇到问题，网关需要XML格式的请求，我的网站和购物车位于PHP，我想要一个解决方案将我的HTML表单值XML格式的服务器，服务器需要下列XML格式：将数据以XML格式发送到服务器通过HTML表格
<html>
<head>
</head>
<body>
<form method="POST" action="https://3ds.cps.lv/GatorServo/request">
<input name="type" value="sendForAuth">
<textarea name="xml">
<?xml version="1.0" encoding="UTF-8" ?>
<cpsxml xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.cps.lv/xml/ns/cpsxml
https://3ds.cps.lv/GatorServo/Gator_SendForAuth.xsd"
xmlns="http://www.cps.lv/xml/ns/cpsxml">
<header xmlns="">
<responsetype>direct</responsetype>
<user>test_sign</user>
<type>sendForAuth</type>
<transType>DB</transType>
<digiSignature>XXXXXXXXXXXXXXXXXXXXXXX</digiSignature>
</header>
<request xmlns="">
<orderNumber></orderNumber>
<cardholder>
<firstName>FirstName</firstName>
<lastName>LastName</lastName>
<street>Street</street>
<zip>54321</zip>
<city>City</city>
<country>LV</country>
<email>[email protected]</email>
<ip>123.124.125.126</ip>
</cardholder>
<amount>
<value>1000</value>
<currency>USD</currency>
</amount>
<product>
<productName>Product Name</productName>
<productUrl>www.test.com</productUrl>
</product>
</request>
</cpsxml>
</textarea>
<input type="submit" value="Send">
</form>
</body>
</html>
这里是我的PHP文件，我一直在使用json2xml尝试，但至今没有运气
<?php
require_once('../assist/cart-load.php');
if(isset($_POST) && isset($_POST['assist'])){
$order_id= $_REQUEST['order_id'];
$a_amount = $_REQUEST['a_total'];
$c_amount = $_REQUEST['c_total'];
$admin_curr = $_REQUEST['a_curr'];
$chk_curr = $_REQUEST['c_curr'];
$checksum = $_SESSION['basket']['security'];
$checksum2 = $_SESSION['basket']['security2'];
}
?>
<html>
<head><title>Complete Your Payment</title>
<script src="json2xml.js" type="text/javascript"></script>
<script type="text/javascript">
var formjson = $('form#payment_form').serializeArray();
//var formxml = $.compactJSON(mjson);
var formxml = json2xml(formjson);
alert(formxml);
$.post("/collect.cgi", { 'data': formxml }, function (data){ });
</script>
</head>
<body>
<form method="post" id="payment_form" name="payment_form" action="https://3ds.cps.lv/GatorServo/request">
<input type="hidden" name="responsetype" value="direct">
<input type="hidden" name="user" value="test_pasta_sign">
<input name="type" type="hidden" value="sendForAuth">
<input type="hidden" name="transType" value="DB">
<input type="hidden" name="digisignature" value="XXXXXXXXXXXXXXXXXXXXXXX">
<p>Order Number</p>
<input type="text" readonly name="orderNumber" value="<?php echo $order_id; ?>">
<p>F Name</p>
<input type="text" name="firstname" value="">
<p>L Name</p>
<input type="text" name="lastname" value="">
<p>Street Address</p>
<input type="text" name="street" value="">
<p>Zip</p>
<input type="text" name="zip" value="">
<p>City</p>
<input type="text" name="city" value="">
<p>Country</p>
<input type="text" name="country" value="">
<p>Email</p>
<input type="text" name="email" value="[email protected]">
<input type="hidden" name="ip" value="123.124.125.126">
<p>Enter Card No.</p>
<input type="text" name="cardNumber" value="">
<p>Enter CVV</p>
<input type="text" name="cvv" value="">
<p>Card Expiry</p>
<input type="text" name="expires" value="">
<p>Amount</p>
<input type="text" name="value" readonly value="<?php echo $a_amount; ?>">
<input type="hidden" name="currency" value="USD">
<p>Product Name</p>
<input type="text" name="productName" value="Product Name" readonly>
<input type="hidden" name="productUrl" value="http://www.test.com">
<input type="submit" value="Send">
</form></body></html>
请给我提供了这个更好的解决方案问题。提前致谢！
UPDATE：现在我已删除了jsontoxml现在使用jquery.ajax，这里是脚本
<script type="text/javascript">
var ajaxurl="https://3ds.cps.lv/GatorServo/request";
var str="";
for(i=0; i<document.payment_form.elements.length; i++)
{
var fieldName = document.payment_form.elements[i].name;
var fieldValue = document.payment_form.elements[i].value;
str += "<" + fieldName + ">" ;
str += fieldValue ;
str += "</" + fieldName + ">" ;
}
$.ajax({
url: ajaxurl,
data: str,
type: 'POST',
contentType: "text/xml",
dataType: "xml",
success : parse_result,
error : show_error
});
function parse_result(xml){
//
}
function show_error(){
//
}
</script>
但现在我得到错误：从服务器“畸形XML请求”。
任何解决方案？
使用'json2xml'的结果是什么？ – madfriend
无效的参数 – Henry