我正在制作一个非常基本的计算器程序(我对Java相当陌生)。我使用java.io.Console包进行命令行输入,并且我的代码看起来像这样的:“找不到符号”错误
import java.io.Console;
public class calculator {
public static void main(String args[]) {
Console console = System.console();
int exit = 1;
System.out.println("Calculator v1.0 by rulla101");
System.out.println(" ");
String inputselect = console.readLine("Type add, sub, mlt, or div to select operation: ");
if (inputselect == "add") {
//ADDING!!!
while(exit > 0) {
String input1a = console.readLine("Input number 1: ");
int a = Integer.parseInt(input1a);
String input2a = console.readLine("Input number 2: ");
int b = Integer.parseInt(input2a);
System.out.println("The answer is:");
System.out.println(a+b);
String exitstringa = console.readLine("Type 0 to exit, type 1 to add two more numbers: ");
int extseta = Integer.parseInt(exitstringa);
if(extseta == 0){
exit--;
}
}
}
else if (inputselect == "sub") {
//SUBTRACTING!
while(exit > 0) {
String input1s = console.readLine("Input number 1: ");
int c = Integer.parseInt(input1s);
String input2s = console.readLine("Input number 2: ");
int d = Integer.parseInt(input2s);
System.out.println("The answer is:");
System.out.println(c-d);
String exitstrings = console.readLine("Type 0 to exit, type 1 to subtract two more numbers: ");
int extsets = Integer.parseInt(exitstrings);
if(exitsets == 0){
exit--;
}
}
}
else if (inputselect == "mlt"){
//MULTIPLYING!!
while(exit > 0) {
String input1m = console.readLine("Input number 1: ");
int e = Integer.parseInt(input1m);
String input2m = console.readLine("Input number 2: ");
int f = Integer.parseInt(input2m);
System.out.println("The answer is:");
System.out.println(e*f);
String exitstringm = console.readLine("Type 0 to exit, type 1 to multiply two more numbers: ");
int extsetm = Integer.parseInt(exitstringm);
if(exitsetm == 0){
exit--;
}
}
}
else if (inputselect == "div"){
//DIVIDING!!
while(exit > 0) {
String input1d = console.readLine("Input number 1: ");
int g = Integer.parseInt(input1d);
String input2d = console.readLine("Input number 2: ");
int h = Integer.parseInt(input2d);
System.out.println("The answer is:");
System.out.println(g/h);
String exitstringd = console.readLine("Type 0 to exit, type 1 to divide two more numbers: ");
int extsetd = Integer.parseInt(exitstringd);
if(exitsetd == 0){
exit--;
}
}
}
}
}
但是,当我试图编译程序时,我得到这个:
/Users/ethan/javafolder/calculator/calculator.java:58: cannot find symbol
symbol : variable exitsets
location: class calculator
if(exitsets == 0){
^
/Users/ethan/javafolder/calculator/calculator.java:83: cannot find symbol
symbol : variable exitsetm
location: class calculator
if(exitsetm == 0){
^
/Users/ethan/javafolder/calculator/calculator.java:106: cannot find symbol
symbol : variable exitsetd
location: class calculator
if(exitsetd == 0){
^
3 errors
Done
我不明白...有问题的变量没有预先定义的或任何.. 。我很确定它们存在于代码中......任何人都可以挑出错误?
(附注:我知道这是真的很笨重,臃肿,我可能可以做到这一点的一半多行,但我承担。请。)
-rulla101
你使用什么编译器(版本/供应商)?另外,尝试将这些变量的分配声明从“int”更改为“Integer”。我真的不知道为什么会这么重要,但'Integer.parseInt'返回一个'Integer'对象(应该在你的赋值中被转换为原始类型,只是好奇而已) –
我正在使用附带的javac编译器Mac OSX,你通过终端执行它 – rulla101
哪个版本的SDK? –