如何访问另一个页面上的mysql变量值

Question

我是新来的PHP，想问我如何访问另一个页面上的变量。 我的代码：

<?php 
    $username = "ADMIN"; 
    $host = "localhost"; 
    $password = "ADMIN"; 
    $database = "USER"; 
    $sname = $_POST['signupname']; 
    $susername = $_POST['susername']; 
    $spassword = $_POST['spassword']; 
    $gender = $_POST['gender']; 
    $con = mysqli_connect($host, $username, $password, $database); 
    if(isset($_POST["signup"])) { 
    mysqli_query($con, "INSERT INTO `USER`.`INFO` (`UID`, `NAME`, `USERNAME`, `PASSWORD`, `GENDER`, `BDAY`, `BMONTH`, `BYEAR`, `STATUS`, `LAST-ACTIVE`) VALUES (NULL, '$sname', '$susername', '$spassword', '$gender', '', '', '', '', NULL);"); 
    echo "<script type='text/javascript'>window.location.replace('../SSTEPS1010101/birthdaycheck1010101.php');</script>"; 
    } 
?> 

和其他页面代码： -

<?php 
    require '../SIGNUP/connects1010101.php'; 
    $bday = $_POST["bday"]; 
    $bmonth = $_POST["bmonth"]; 
    $byear = $_POST["byear"]; 
    if (isset($_POST["snext"])) { 
    mysqli_query($con, "UPDATE `USER`.`INFO` SET `BDAY` = '$bday', `BMONTH` = '$bmonth', `BYEAR` = '$byear' WHERE `info`.`USERNAME` = '$susername;'"); 
    } 
    echo "$susername"; 
?> 

我怎样才能其它页面上访问$susername？ 我正在使用$ _SESSIONS [“susername”];并在第一页回显它，它正在工作，但在另一页上$ _SESSIONS [“susername”];不管用。

Answer 1

1.使用会话：

Fisrt.php

session_start(); 
$username = "Max"; 
$username=$_SESSION['username']; 
echo $username; //Output: Max 

用法在另一页

session_start(); 
echo $_SESSION['username']; //Output: Max 

包括

可以，但在你上的变量包括将覆盖该变量在你的第一个：

myfirstfile.php

$name = 'max'; 

mysecondfile.php

$city = 'xyz'; 

test.php的

include 'myfirstfile.php'; 
echo $name; 

include 'mysecondfile.php'; 
echo $city; 

输出：

最大

XYZ

Answer 2

您可以使用全局关键字或会话

global $susername; 

或随着会议

session_start(); 
$username = "bla bla bla"; 
$_SESSION['username']=$username; 

另一页：

session_start(); 
$username=$_SESSION['username']; 
echo $username; 

Answer 3

您包括使用require*和include*功能的文件，当你有文件，你需要指定正确的文件路径。

设置你的PHP显示错误

ini_set('display_errors', 1); 
ini_set('display_startup_errors', 1); 
error_reporting(E_ALL); 

如何包括文件

// including a file which is in the same directory 
require_once ('somefile.php'); 

// include a file that is one directories back 
require_once ('../somefile.php'); 
require_once ('../directory/somefile.php'); 

// include a file that is two directories back 
require_once ('../../somefile.php'); 
require_once ('../../directory/somefile.php'); 

// etc 

Answer 4

尝试......

connects1010101.php文件

<?php 
//connects1010101.php File 


    $username = "ADMIN"; 
    $host = "localhost"; 
    $password = "ADMIN"; 
    $database = "USER"; 

    $sname = $_POST['signupname']; 
    $susername = $_POST['susername']; 
    $spassword = $_POST['spassword']; 
    $gender = $_POST['gender']; 

    $con = mysqli_connect($host, $username, $password, $database); 

    if(isset($_POST["signup"])) { 

    mysqli_query($con, "INSERT INTO `USER`.`INFO` (`UID`, `NAME`, `USERNAME`, `PASSWORD`, `GENDER`, `BDAY`, `BMONTH`, `BYEAR`, `STATUS`, `LAST-ACTIVE`) VALUES (NULL, '$sname', '$susername', '$spassword', '$gender', '', '', '', '', NULL)"); 

    echo "<script type='text/javascript'>window.location.replace('../SSTEPS1010101/birthdaycheck1010101.php');</script>"; 
    } 
?> 

AnotherFile.php

<?php 

    include '../SIGNUP/connects1010101.php'; //connects1010101.php include 
    global $susername; 

    $bday = $_POST["bday"]; 
    $bmonth = $_POST["bmonth"]; 
    $byear = $_POST["byear"]; 

    if (isset($_POST["snext"])) { 

    mysqli_query($con, "UPDATE `USER`.`INFO` SET `BDAY` = '$bday', `BMONTH` = '$bmonth', `BYEAR` = '$byear' WHERE `USERNAME` = '$susername' "); 
    } 

    echo "$susername"; 
?> 

Answer 5

谢谢大家。主要问题在于重定向。 我的旧代码： -

<?php 
    $username = "ADMIN"; 
    $host = "localhost"; 
    $password = "ADMIN"; 
    $database = "USER"; 
    $sname = $_POST['signupname']; 
    $susername = $_POST['susername']; 
    $spassword = $_POST['spassword']; 
    $gender = $_POST['gender']; 
    $con = mysqli_connect($host, $username, $password, $database); 
    if(isset($_POST["signup"])) { 
    mysqli_query($con, "INSERT INTO `USER`.`INFO` (`UID`, `NAME`, `USERNAME`, `PASSWORD`, `GENDER`, `BDAY`, `BMONTH`, `BYEAR`, `STATUS`, `LAST-ACTIVE`) VALUES (NULL, '$sname', '$susername', '$spassword', '$gender', '', '', '', '', NULL);"); 
    echo "<script type='text/javascript'>window.location.replace('../SSTEPS1010101/birthdaycheck1010101.php');</script>"; 
    } 
?> 

其他页： -

<?php 
    require '../SIGNUP/connects1010101.php'; 
    $bday = $_POST["bday"]; 
    $bmonth = $_POST["bmonth"]; 
    $byear = $_POST["byear"]; 
    if (isset($_POST["snext"])) { 
    mysqli_query($con, "UPDATE `USER`.`INFO` SET `BDAY` = '$bday', `BMONTH` = '$bmonth', `BYEAR` = '$byear' WHERE `info`.`USERNAME` = '$susername;'"); 
    } 
    echo "$susername"; 
?> 

我的新首页代码： -

<?php 
session_start(); 
$username = "ADMIN"; 
$host = "localhost"; 
$password = "chmuhammadsohaib123"; 
$database = "USER"; 
$sname = $_POST['signupname']; 
$susername = $_POST['susername']; 
$spassword = $_POST['spassword']; 
$gender = $_POST['gender']; 
$con = mysqli_connect($host, $username, $password, $database); 
if(isset($_POST["signup"])) { 
mysqli_query($con, "INSERT INTO `USER`.`INFO` (`UID`, `NAME`, `USERNAME`, `PASSWORD`, `GENDER`, `BDAY`, `BMONTH`, `BYEAR`, `STATUS`, `LAST-ACTIVE`) VALUES (NULL, '$sname', '$susername', '$spassword', '$gender', '', '', '', '', NULL);"); 
$snusername = $_SESSION["susername"] = $susername; 
} 
if (isset($_POST["signup"])) { 
    echo "<script type='text/javascript'>window.location.replace('../SSTEPS1010101/birthdaycheck1010101.php');</script>"; 
}?> 

其他页： -

<?php 
session_start(); 
require_once ('../SIGNUP/connects1010101.php'); 
$bday = $_POST["bday"]; 
$bmonth = $_POST["bmonth"]; 
$byear = $_POST["byear"]; 
$snusername = $_SESSION["susername"]; 
if (isset($_POST["snext"])) { 
mysqli_query($con, "UPDATE `USER`.`INFO` SET `BDAY` = '$bday', `BMONTH` = '$bmonth', `BYEAR` = '$byear' WHERE `info`.`USERNAME` = '$snusername;'"); 
}?> 

的主要问题在于我的JS脚本使用。感谢所有回答的guyz。