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任何人都可以帮助下面的请。我的头脑很难找到如何让它工作。如何将PHP代码整合到HTML Carousel代码中?
该代码适用于缩略图旋转木马。
下面是HTML
<div class="carousel slide" id="myCarousel">
<!-- Carousel items -->
<div class="carousel-inner">
<div class="active item" data-slide-number="0">
<img src="http://placehold.it/770x300&text=one">
</div>
<div class="item" data-slide-number="1">
<img src="http://placehold.it/770x300&text=two">
</div>
<div class="item" data-slide-number="2">
<img src="http://placehold.it/770x300&text=three">
</div>
<div class="item" data-slide-number="3">
<img src="http://placehold.it/770x300&text=four">
</div>
<div class="item" data-slide-number="4">
<img src="http://placehold.it/770x300&text=five">
</div>
<div class="item" data-slide-number="5">
<img src="http://placehold.it/770x300&text=six">
</div>
</div>
<!-- Carousel nav -->
<a class="left carousel-control" href="#myCarousel" role="button" data-slide="prev">
<span class="glyphicon glyphicon-chevron-left"></span>
</a>
<a class="right carousel-control" href="#myCarousel" role="button" data-slide="next">
<span class="glyphicon glyphicon-chevron-right"></span>
</a>
</div>
<!--thumbnails-->
<div class="row hidden-xs" id="slider-thumbs">
<ul class="hide-bullets">
<li class="col-sm-2">
<a class="thumbnail" id="carousel-selector-0">
<img src="http://placehold.it/170x100&text=one">
</a>
</li>
<li class="col-sm-2">
<a class="thumbnail" id="carousel-selector-1">
<img src="http://placehold.it/170x100&text=two">
</a>
</li>
<li class="col-sm-2">
<a class="thumbnail" id="carousel-selector-2">
<img src="http://placehold.it/170x100&text=three">
</a>
</li>
<li class="col-sm-2">
<a class="thumbnail" id="carousel-selector-3">
<img src="http://placehold.it/170x100&text=four">
</a>
</li>
<li class="col-sm-2">
<a class="thumbnail" id="carousel-selector-4">
<img src="http://placehold.it/170x100&text=five">
</a>
</li>
<li class="col-sm-2">
<a class="thumbnail" id="carousel-selector-5">
<img src="http://placehold.it/170x100&text=six">
</a>
</li>
</ul>
</div>
上面的代码工作正常,但我想,这样的滑块与缩略图动态画面,整合以下PHP代码。
这里是PHP代码来显示图像:
<?php
if ($images = get_field('images', $design_id)) {
foreach ($images as $image) {
echo '<img src="' . $image['image']['sizes']['large'] . '" />';
}
}
?>
如果有人可以帮助或点我在正确的方向,我们将不胜感激!
谢谢@ bksi让我的幻灯片工作。如果($ images = get_field('images',$ design_id))foreach($ images = $ key => $ image){ $ active = $ key == 0? '主动':''; echo'
如果它可以帮助你标记是正确的答案。 – bksi 2014-10-02 09:07:26