如何等待线程完成运行？Thread.join使我的主线程无响应？

Question

我正在使用Windows应用程序发送邮件给多个用户的项目，但发生的是，当我使用Thread.Join（）方法时，它使我的主UI不响应...... 什么我想要的是....我想在单独的线程上运行SMTPClienTSetting（）方法，并希望我的主UI保持对其他工作的响应。我想在后台运行此邮件发送活动...请使用线程提示我只有概念.....

public void SendMail(dataset ds) 
     { 
          for(inti=0<ds.Tables[0].Rows.Count<i++) 
          { 

           Thread tMail = new Thread(() => { 
            resValue = SMTPClienTSetting(ds, mail); 

           }); 
           tMail.IsBackground = true; 
           tMail.Start(); 
           tMail.Join(); 
           if (resValue == "True") 
           { 
            Thread tPopUp = new Thread(new ThreadStart(this.ShowMessagePopUp)); 
            tPopUp.IsBackground = true; 
            this.BeginInvoke((MethodInvoker)delegate{ 
          }); 
            tPopUp.Start(); 
            lblPOpUpInfo = "Message sent successfully to \nAsset Owner : " + AssetOwner + "\n" + "Email : " + RecipientID; 

           } 
           else 
           { 
            Thread tPopUp = new Thread(new ThreadStart(this.ShowMessagePopUp)); 
            tPopUp.IsBackground = true; 
                   this.BeginInvoke((MethodInvoker)delegate{ 
          }); 
            tPopUp.Start(); 
            lblPOpUpInfo = "Message sending failed to \nAsset Owner :" + AssetOwner + "\n" + "Email : " + RecipientID + "!!!\nPlease check your SMTP details and\nInternet Connection..!!!"; 
           } 
         } 
     } 
     #region Function for setting SMTP Client 
       public string SMTPClienTSetting(DataSet ds, MailMessage MailstoSend) 
       { 
        try 
        { 
         SmtpClient objsmtp = new SmtpClient(); 
         NetworkCredential NetAccess = new NetworkCredential(); 

         NetAccess.UserName = ds.Tables[0].Rows[0][0].ToString(); 
         //NetAccess.Password = base64Decode(ds.Tables[0].Rows[0][1].ToString()); 

         NetAccess.Password = genFunc.base64Decode(ds.Tables[0].Rows[0][1].ToString()); 
         objsmtp.Credentials = NetAccess; 

         objsmtp.Host = ds.Tables[0].Rows[0][2].ToString(); 
         objsmtp.Port = Convert.ToInt16(ds.Tables[0].Rows[0][3].ToString()); 

         objsmtp.Send(MailstoSend); 

         //System.Threading.Thread.Sleep(500); 

         return "True"; 
        } 
        catch (NullReferenceException nr) 
        { 
         return nr.Message; 
        } 
        catch (Exception ex) 
        { 
         return ex.Message; 
        } 
       } 
       #endregion 
     } 

    #region Function to show Pop Up window using separate thread 
    public void ShowMessagePopUp() 
    { 
      try 
      { 
       frmHomePopUp homePopUp = new frmHomePopUp(); 
       mailTimer.Elapsed += delegate { mailTimer.Stop(); homePopUp.Close(); }; 
       //mailTimer.Elapsed += this.TimeEvent; 
       mailTimer.Interval=5000; 
       mailTimer.Enabled = true; 
       homePopUp.lblInfo.Text = lblPOpUpInfo; 
       homePopUp.Refresh(); 
       mailTimer.Start(); 
       homePopUp.ShowDialog(); 

      } 
      catch (Exception ex) 
      { 
       MessageBox.Show(ex.Message); 
      } 

    } 
    #endregion 

    public void mailTimer_Elapsed(object source, EventArgs e) 
    { 
     //frmHome home; 
     mailTimer.Stop(); 
     } 

Answer 1

基本上：不要用Thread.Join; 是什么是块。

适当的做法是在辅助方法结束做任何UI工作：

Thread tMail = new Thread(() => { 
    resValue = SMTPClienTSetting(ds, mail); 

    if (resValue == "True") { 
     // blah blah blah 
    } 
    // now: if you need to update any UI state: 
    this.BeginInvoke((MethodInvoker)delegate { 
     someControl.Text = lblPOpUpInfo; // for example 
    }); 
}); 
tMail.IsBackground = true; 
tMail.Start(); 

的呼叫Invoke/BeginInvoke切换回UI线程，基本上工作作为一个回调。

请注意，您可能还想在此处使用ThreadPool而不是Thread。