在机器人即时通讯新的,试图让简单的程序,可以在的AsyncTask类印刷可变 这里是我的代码的AsyncTask类运行时错误:concurrent.FutureTask.finishCompletion
int a,b,c;
@Override
protected String doInBackground(String... arg0) {
// TODO Auto-generated method stub
a =10;
b=10;
c=a+b;
Context ctx = null;
show(c, ctx);
return null;
}
public void show(int c2 ,Context c) {
// TODO Auto-generated method stub
Toast.makeText(c, "AsyncTask classs + c2 ", Toast.LENGTH_SHORT).show();
}
运行此程序,即时通讯之后越来越运行时错误
这里我们logcat的文件视图
Process: com.example.asycclass, PID: 2539
java.lang.RuntimeException: An error occured while executing doInBackground()
at android.os.AsyncTask$3.done(AsyncTask.java:300)
at java.util.concurrent.FutureTask.finishCompletion(FutureTask.java:355)
at java.util.concurrent.FutureTask.setException(FutureTask.java:222)
at java.util.concurrent.FutureTask.run(FutureTask.java:242)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:231)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587)
at java.lang.Thread.run(Thread.java:841)
Caused by: java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()
at android.os.Handler.<init>(Handler.java:200)
at android.os.Handler.<init>(Handler.java:114)
at android.widget.Toast$TN.<init>(Toast.java:327)
at android.widget.Toast.<init>(Toast.java:92)
at android.widget.Toast.makeText(Toast.java:241)
at com.example.asycclass.MainActivity$AttemptLogin.show(MainActivity.java:74)
at com.example.asycclass.MainActivity$AttemptLogin.doInBackground(MainActivity.java:65)
at com.example.asycclass.MainActivity$AttemptLogin.doInBackground(MainActivity.java:1)
at android.os.AsyncTask$2.call(AsyncTask.java:288)
at java.util.concurrent.FutureTask.run(FutureTask.java:237)
你传递一个空的上下文来秀方法 – 2014-12-13 05:43:13
@Pramod亚达夫然后我应该通过什么?任何解决方案将帮助我完成我的项目感谢 – 2014-12-13 05:47:03
你的asynctask是一个活动的内部类或一个单独的类 – 2014-12-13 05:50:31