Android如何获取字符串的第一个字符？

Question

如何获取字符串的第一个字符？

string test = "StackOverflow"; 

第一个字符= “S”

Answer 1

String test = "StackOverflow"; 
char first = test.charAt(0); 

Answer 2

另一种方式是

String test = "StackOverflow"; 
String s=test.substring(0,1); 

在此你有导致String

Answer 3

使用的charAt（）：

public class Test { 
    public static void main(String args[]) { 
     String s = "Stackoverflow"; 
     char result = s.charAt(0); 
     System.out.println(result); 
    } 
} 

这是一个tutorial

Answer 4

正如大家所说，这里是完整的代码片段。

public class StrDemo 
{ 
public static void main (String args[]) 
{ 
    String abc = "abc"; 

    System.out.println ("Char at offset 0 : " + abc.charAt(0)); 
    System.out.println ("Char at offset 1 : " + abc.charAt(1)); 
    System.out.println ("Char at offset 2 : " + abc.charAt(2)); 

    //Also substring method 
    System.out.println(abc.substring(1, 2)); 
    //it will print 

BC

// as starting index to end index here in this case abc is the string 
    //at 0 index-a, 1-index-b, 2- index-c 

// This line should throw a StringIndexOutOfBoundsException 
    System.out.println ("Char at offset 3 : " + abc.charAt(3)); 
} 
} 

回到这个link，读取点4