下面是我的JSON字符串样本格式:如何在ios中创建json?
{"entry":{"user":{"id":5,"name":"testuser"},"startday":"2015-12-27","status":"New","total":0.0,"entries":[{"id":752,"typename":{"id":3,"name":"teste"},"typetypeissue":{"id":4},"user":{"id":5,"name":"testuser
"},"activity":{"id":8,"name":"Design"},"time":4.0,"comments":"","Date":"2015-12-27"},{"id":750,"typename":{"id":2,"name":"teste1"},"typeissue":{"id":13},"user":{"id":5,"name":"testuser
"},"activity":{"id":8,"name":"Design"},"time":4.0,"comments":"","Date":"2015-12-29"}]}}
的“项”部分比行值了。请帮助我如何创建一个json格式。用户输入的记录数超过值“条目”部分。
创建一个新的* * JSON!?以什么方式*新*? – luk2302
欢迎来到堆栈溢出!请阅读[如何问好问题](// stackoverflow.com/help/how-to-ask)并尝试编辑您的问题。有了高质量的问题,您将会收到更快的答案。谢谢! – SmokeDispenser
NSString * string = @“这里是你的json字符串”;如何以编程方式创建json字符串。 – Baskar