2015-02-10 39 views
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我建立一个POS应用VeriFone公司(C语言),它应与来自摩洛哥M2M开关通信,但发送应该有这样(08\00)但反斜线初始化消息时,我被困当发送这个我有08\5c00。 它用十六进制(5c)中的值转换反斜杠。我正在使用的工具是套接字工作台来模拟服务器。 如何在不转换为\5c的情况下发送反斜杠? 它需要用C语言完成。发送一个反斜杠用C插座ISO8583消息

编辑

这是我要发送到与头中的服务器上的数据,但尝试打印\00当我\5C00

sprintf(data,"%s%s%s%s%s%s%s%s%s%s%s%s%s","\x30\x60\x60\x20\x15\x35\x35","\x08",‌"\\00","\x0x00","\x01\x30\x30\x30\x30\xC0\x30\x30\x30\x30","\x97","\\00","\x30\x30"‌,"\x00\x00\x01\x00","\x02",idTerminal,idCommercant,"\x20\x20\x20\xA4\xBC"); 
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向我们展示相关的部分代码的。 – 2015-02-10 11:32:31

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也许服务器正在接收'\',但将其打印为'\ 5c'? – 2015-02-10 11:43:35

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这是我想向服务器发送与它的头,但是当我要打印\ 00我有\ 5C00数据:\t \t \t的sprintf(数据,“%s%s%S%S%s%S% S%S%S%S%S%S%S “ ”\ X30 \ X60 \ X60 \ X20 \ X15 \ X35 \ X35“, ”\ X08“, ”\\ 00“, ”\ x0x00“,” \ X01 \ X30 \ X30 \ X30 \ X30 \ XC0 \ X30 \ X30 \ X30 \ X30" , “\ X97”, “\\ 00”, “\ X30 \ X30”, “\ X00 \ X00 \ X01 \ X00” “\ X02”,idTerminal,idCommercant, “\ X20 \ X20 \ X20 \ XA4 \ XBC”); – knk 2015-02-10 13:18:34

回答

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如果我理解正确的话,第一部分你的例子:

sprintf(data,"%s%s", 
      "\x30\x60\x60\x20\x15\x35\x35", 
      "\x08"); 

正在做你想要的。问题是,在接下来的%s,你正在使用"\\00",你想服务器接收ASCII \00(这将是0x5c,为0x30,的0x30),而是服务器报告它接收ASCII \5c00(这将是0x5c, 0x,35,0x43,0x30,0x30)。

我克拉斯Lindbäck同意的,因为它听起来像的VeriFone终端正在做正确的事情,但服务器显示是错误的。为了证明这是正确的(你可以只做一个或另一个,或者你可以一起做),我会考虑做两件事来排除这种情况。

第一条:您可以使用LOG_PRINTF(或者打印到纸张或屏幕上,如果你喜欢)打印每个字节的值,你把它关闭之前。下面是我写过的一个快速而肮脏的函数,当我对一次类似的问题进行故障排除时。请注意,我只关心字符串的开头(如你所见,似乎是这样),所以如果我用完了缓冲区空间,我不打印结尾。

void LogDump(unsigned char* input, int expectedLength) 
{ 
#ifdef LOGSYS_FLAG 
    char buffer[100]; 
    int idx, bfdx; 
    memset(buffer, 0, sizeof(buffer)); 

    bfdx = 0; 
    for (idx = 0; idx < expectedLength && bfdx < sizeof(buffer); idx++) 
    { 
     //if it is a printable character, print as is 
     if (input[idx] > 31 && input[idx] < 127) 
     { 
      buffer[bfdx++] = (char) input[idx]; 
      continue; 
     } 
     //if we are almost out of buffer space, show that we are truncating 
     // the results with a ~ character and break. Note we are leaving 5 bytes 
     // because we expand non-printable characters like "<121>" 
     if (bfdx + 5 > sizeof(buffer)) 
     { 
      buffer[bfdx++] = '~'; 
      break; 
     } 
     //if we make it here, then we have a non-printable character, so we'll show 
     // the value inside of "<>" to visually denote it is a numeric representation 
     sprintf(&buffer[bfdx], "<%d>", (int) input[idx]); 
     //advance bfdx to the next 0 in buffer. It will be at least 3... 
     bfdx += 3; 
     //... but for 2 and 3 digit numbers, it will be more. 
     while (buffer[bfdx] > 0) 
      bfdx++; 
    } 
    //I like to surround my LOG_PRINTF statements with short waits because if there 
    // is a crash in the program directly after this call, the LOG_PRINTF will not 
    // finish writing to the serial port and that can make it look like this LOG_PRINTF 
    // never executed which can make it look like the problem is elsewhere 
    SVC_WAIT(5); 
    LOG_PRINTF(("%s", buffer)); 
    SVC_WAIT(5); 
#endif 
} 

其次:尝试为char数组中的每个位置分配一个显式值。如果您已经使用了我的LOG_PRINTF建议,并且发现它并未发送您认为应该的内容,则这将是解决此问题的一种方法,以便它能够正确发送您想要的内容。这种方法比较繁琐一些,但因为你是拼写出来的每个值,无论如何,它应该不会太大更多的开销:

data[0] = 0x30; 
//actually, I'd probably use either the decimal value: data[0] = 48; 
// or I'd use the ASCII value: data[0] = '0'; 
// depending on what this data actually represents, either of those is 
// likely to be more clear to whomever has to read the code later. 
// However, that's your call to make. 
data[1] = 0x60; 
data[2] = 0x60; 
data[3] = 0x20; 
data[4] = 0x15; 
data[5] = 0x35; 
data[6] = 0x35; 
data[7] = 0x08; 
data[8] = 0x5C; // This is the '\' 
data[9] = 0x48; // The first '0' 
data[10]= 0x48; // The second '0' 
data[11]= 0; 
//for starters, you may want to stop here and see what you get on the other side 

后你已经证明自己,这ISVeriFone代码不是导致问题,您将知道您是需要关注终端还是服务器端。

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我意识到这是一个非常古老的职位(我不知道我今天之前没有看到它...),你可能已经解决了你的问题。如果你有*解决了它,你会分享你的解决方案吗? @knk – David 2015-07-24 18:14:08