使用linq动态添加节点在xml中使用linq

Question

我想在xml中动态添加节点，文件数组包含大号。的文件，所以我想避免写这个声明新的XElement（“文件名”，文件[0]）。有没有办法在这个语句或任何其他方式上运行for/foreach循环来实现这个目标。

string [] sep = { ",",";" }; 
string[] files = txtFiles.Text.Split(sep, StringSplitOptions.RemoveEmptyEntries); 

XDocument xdoc = new XDocument(
        new XDeclaration("1.0", "utf-16", "true"), 
        new XElement("data", 
         new XElement("rn", 
          new XAttribute("Active", "true"), 
          new XAttribute("Name", txtReportName.Text), 
         new XElement("Files", 
          new XElement("FileName",files[0]), 
          new XElement("FileName",files[1]), 
          new XElement("FileName",files[2]))))); 

输出：

<data> 
<rn Active="true" Name="testdata"> 
<Files> 
    <FileName>file1</FileName> 
    <FileName>file2</FileName> 
    <FileName>file3</FileName> 
</Files> 
</rn> 
</data> 

Answer 1

string [] sep = { ",",";" }; 
string[] files = txtFiles.Text.Split(sep, StringSplitOptions.RemoveEmptyEntries); 

XDocument xdoc = new XDocument(
        new XDeclaration("1.0", "utf-16", "true"), 
        new XElement("data", 
         new XElement("rn", 
          new XAttribute("Active", "true"), 
          new XAttribute("Name", txtReportName.Text), 
         new XElement("Files", 
          files.Select(x => new XElement("FileName", x))))));