据this post,花哨的动画被内置到并删除它,你将需要重写ControlTemplate
您Button
。幸运的是,这并不难。我用this post作为源材料,并提出了以下Style
,给你的想法。
<Style x:Key="MouseOverButtonStyle" TargetType="Button">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="Button">
<ControlTemplate.Resources>
<Style x:Key="ShadowStyle">
<Setter Property="Control.Foreground" Value="LightGray" />
</Style>
</ControlTemplate.Resources>
<Border Name="border" BorderThickness="1" Padding="4,2" BorderBrush="DarkGray" CornerRadius="3" Background="{TemplateBinding Background}">
<Grid >
<ContentPresenter HorizontalAlignment="Center" VerticalAlignment="Center" Name="contentShadow" Style="{StaticResource ShadowStyle}">
<ContentPresenter.RenderTransform>
<TranslateTransform X="1.0" Y="1.0" />
</ContentPresenter.RenderTransform>
</ContentPresenter>
<ContentPresenter HorizontalAlignment="Center" VerticalAlignment="Center" Name="content"/>
</Grid>
</Border>
</ControlTemplate>
</Setter.Value>
</Setter>
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Background" Value="Beige" />
</Trigger>
</Style.Triggers>
</Style>
更新: 如果您在应用代码中的Style
是死心塌地,你不希望使用ResourceDictionary
(可能是更好的方式来做到这一点),可以动态加载Style
使用XamlReader.Load
:
const string xaml = @"
<Style xmlns='http://schemas.microsoft.com/winfx/2006/xaml/presentation'
xmlns:x='http://schemas.microsoft.com/winfx/2006/xaml'
TargetType='Button'>
<Setter Property='Template'>
<!--- Omitted For Clarity --->
</Setter>
<Style.Triggers>
<Trigger Property='IsMouseOver' Value='True'>
<Setter Property='Background' Value='Beige' />
</Trigger>
</Style.Triggers>
</Style>";
var encoding = new ASCIIEncoding();
var bytes = encoding.GetBytes(xaml);
var style = (Style)XamlReader.Load(new MemoryStream(bytes));
Button1.Style = style;
我知道我可以通过XAML做到这一点,但不能通过C#完成? – Luiscencio 2010-04-22 01:43:54
您可以将样式放在资源字典中,然后在需要应用到按钮时将其拉出。 – 2010-04-22 02:03:17
+1我会尝试你的更新,它看起来很有前途,谢谢 – Luiscencio 2010-04-22 14:04:58