2012-11-27 51 views
0

这仍然没有运行,但希望它会给一些更多的信息 限制文件清单:我有这段代码:从XML文件失败

#import modules 
import os, sys, datetime, time 
# sys.setdefaultencoding is cancelled by site.py 
reload(sys) # to re-enable sys.setdefaultencoding() 
sys.setdefaultencoding('utf-8') 
try: 
    import xml.etree.cElementTree as ET 
except ImportError: 
    import xml.etree.ElementTree as ET 

now = datetime.datetime.now() 
today = now.strftime("%m/%d/%Y") 
processed = 0 
    #here if sync_list.xml doesn't exist, I ask for some user input i want to save between sessions 
    #then I save that info to sync_list.xml, along with the element to store files already synced 
    root = ET.Element("root") 

    synced = ET.SubElement(root, "synced") 
    synced.set("name", "Already Synced") 
    sfile = ET.SubElement(synced, "sfile") 
    sfile.set("date", today) 
    sfile.text = "firstsync" 

    tree = ET.ElementTree(root) 
    tree.write("sync_list.xml") 
#If sync_list.xml already exists, then I grab the info 
tree = ET.parse("sync_list.xml") 
root = tree.getroot() 
#I pull in all the info I need to work with and: 
for elem in root.findall('sfile'): 
    synced = elem.text 
dcheck = 0 
for elem in root.findall('synced/sfile'): 
    fdate = elem.attrib.get('date') 
    if fdate == today: 
    dcheck += 1 
synced = [elt.text for elt in root.findall('synced/sfile')] 
#if sync_list.xml exists get the list of (UUIDs) $entries that have already been synced, and exclude them from the current query. If no UUID's exist in sync_list.xml, ignore 
synclimit = 10 - dcheck 
print "Already synced today: " + str(dcheck) 
print "Today's synclimit: " + str(synclimit) 
if synclimit == 0: 
    print "Sorry, you've reached your limit for file syncing today. The limit is reset each night at 12:00 a.m." 
    sys.exit() 
synclimit = int(raw_input("How many files do you want to sync today? You have a max amount of " + str(synclimit) + " left today: ")) 

for filename in os.listdir(filepath): 
    if processed >= synclimit: 
     print "You've successfully synced " + str(synclimit) + " files." 
     sys.exit() 
    else: 
     if filename.endswith('.txt') and filename not in synced: 
      filename = os.path.join(filepath, filename) 
      #process the files. This is where I'm getting variable dofilename 
      #The processing works correctly. It's just going over the same files that have already been synced 

      tree = ET.parse('sync_list.xml') 
      synced = tree.find('synced') 
      sfile = ET.SubElement(synced, "sfile", date=today) 
      sfile.text = dofilename 

      tree.write('sync_list.xml', encoding='utf-8', xml_declaration=True) 
      processed += 1 

      print 'Synced ' + dofilename + '....>' 

print 'done!' 

和它是什么意思做的是检查sync_list文件名,而不是处理这些文件。

预期输出: 如果我有一个目录:

,我跑在第1天的剧本为5的synclimit,我希望将XML输出看起来像:

<sfile date="11/26/2012">file1.txt</sfile> 
<sfile date="11/26/2012">file2.txt</sfile> 
<sfile date="11/26/2012">file3.txt</sfile> 
<sfile date="11/26/2012">file4.txt</sfile> 
<sfile date="11/26/2012">file5.txt</sfile> 

这个按预期工作,但如果我在第二天以10的同步限制运行它,我会得到:

<sfile date="11/26/2012">file1.txt</sfile> 
<sfile date="11/26/2012">file2.txt</sfile> 
<sfile date="11/26/2012">file3.txt</sfile> 
<sfile date="11/26/2012">file4.txt</sfile> 
<sfile date="11/26/2012">file5.txt</sfile> 
<sfile date="11/27/2012">file1.txt</sfile> 
<sfile date="11/27/2012">file2.txt</sfile> 
<sfile date="11/27/2012">file3.txt</sfile> 
<sfile date="11/27/2012">file4.txt</sfile> 
<sfile date="11/27/2012">file5.txt</sfile> 
<sfile date="11/27/2012">file6.txt</sfile> 
<sfile date="11/27/2012">file7.txt</sfile> 

我所期待的,会是这样,无论什么synclimit设置为,该脚本将跳过已经被处理过这些文件,而是给我这样的输出:

<sfile date="11/26/2012">file1.txt</sfile> 
<sfile date="11/26/2012">file2.txt</sfile> 
<sfile date="11/26/2012">file3.txt</sfile> 
<sfile date="11/26/2012">file4.txt</sfile> 
<sfile date="11/26/2012">file5.txt</sfile> 
<sfile date="11/27/2012">file6.txt</sfile> 
<sfile date="11/27/2012">file7.txt</sfile> 

感恩对于任何指导,关于我误入歧途的地方。

+0

你的代码没有什么明显的错误,但是它没有足够的能够运行它。你可以发布一个运行的例子(包括输入数据和预期输出)并显示问题。这将使我们更容易测试它。 – aquavitae

+0

制作一个简单的文件(例如'done_list.csv'),并在当天存储一个处理文件列表;然后在程序开始时使用此文件在第二天(将来日期)进行验证;(例如:您可以验证已处理的日期为'26'的任何文件此次不会处理(在'27 'th)..并在每次处理后更新该文件中的信息..。简单.. – namit

+0

我以为这就是我在用'if filename.endswith('。txt')和文件名不在同步:我正在检查sync_list.xml以确保条目尚未同步,如果是,我希望它会跳过它。 – sosukeinu

回答

1

简单的问题,我只是没有看到它。将新条目写入sync_list.xml时,我正在重新定义synced

synced = ET.SubElement(root, "synced") 

将其更改为不同的变量固定everthing。谢谢。