Mysql组concat，然后根据结果查询

大家好，我有一个表业务，有很多关系很多。有人建议我先执行组concat以从多个表中获取想法，然后查看这些ID以从多个表中获取值Mysql组concat，然后根据结果查询

在下面的实例中，我可以看到我获取了公告ID列表通过GROUP_CONCAT（DISTINCT ba.announcement_id）的 '公告'，是如何从这里做我设置

SELECT * FROM公告放回原处身份证件（_ __ _ __ _）

，其中在代表着什么从GROUP_CONCAT返回

ID B

BEGIN

/* Business Information and Categories */ 
SELECT 
    b.alias_title, b.title, b.premisis_name, 
    a.address_line_1, a.address_line_2, a.postal_code,tvc.town_village_city,spc.state_province_county, c.country, 
    GROUP_CONCAT(DISTINCT be.event_id) as 'event', 
    GROUP_CONCAT(DISTINCT ba.announcement_id) as 'announcement', 
    GROUP_CONCAT(DISTINCT bd.document_id) as 'document', 
    GROUP_CONCAT(DISTINCT bi.image_id) as 'image', 
    GROUP_CONCAT(DISTINCT bprod.product_id) as 'product', 
    GROUP_CONCAT(DISTINCT bt.tag_title_id) as 'tag' 
    FROM business AS b 
    INNER JOIN business_category bc_1 ON b.primary_category = bc_1.id 
    INNER JOIN business_category bc_2 ON b.secondary_category = bc_2.id 
    LEFT OUTER JOIN business_category bc_3 ON b.tertiary_category = bc_3.id 
    INNER JOIN address a ON b.address_id = a.id 
    LEFT OUTER JOIN town_village_city tvc ON a.town_village_city_id = tvc.id 
    LEFT OUTER JOIN state_province_county spc ON a.state_province_county_id 
    INNER JOIN country c ON a.country_id = c.id 
    LEFT OUTER JOIN geolocation g ON b.geolocation_id = g.id 
    LEFT OUTER JOIN business_event be ON b.id = be.event_id 
    LEFT OUTER JOIN business_announcement ba ON b.id = ba.announcement_id 
    LEFT OUTER JOIN business_document bd ON b.id = bd.business_id 
    LEFT OUTER JOIN business_image bi ON b.id = bi.business_id 
    LEFT JOIN business_property bp ON b.id= bp.business_id 
    LEFT JOIN business_product bprod ON b.id= bprod.business_id 
    LEFT JOIN business_tag bt ON b.id = bt.business_id 
    WHERE b.id= in_business_id; 

    SELECT * from announcement 
    where 




END

来源

2012-09-29 Matthew Chambers

在你的第一个SELECT语句，你可以指定announcementId的一个变量，然后用它来获得所有公告在第二个查询：

set @announcementIds = ''; 
select ..........., 
@announcementIds:= GROUP_CONCAT(DISTINCT announcement_id) as 'announcement', 
...........; 

Select * from announcement 
where announcement_id REGEXP REPLACE(@announcementIds,',','|');

一些链接：

来源

2012-09-29 16:39:32 kasi

Mysql组concat，然后根据结果查询

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