分割和合并多维数组红宝石

Question

我有一个多维数组这样的：

@splited_array = Array.new 
@original_array.each do |elem| 
    @tmp = Array.new 
    elem.each_slice(10) do |row| 
    @tmp << row 
    end 
    @splited_array << @tmp 
end 

# Result: 
# splited_array[0][0] => labels 1 to 9 
# splited_array[0][1] => labels 10 to 19 
# splited_array[1][0] => values 1 to 9 
# splited_array[1][1] => values 10 to 19 

现在我将合并到这样的结果：

original_array[0] = Array(20 elements) # Titles 
original_array[1] = Array(20 elements) # Values 

我曾经10列splited这阵

# splited_array[0][0] => labels 1 to 9 
# splited_array[0][1] => values 1 to 9 
# splited_array[1][0] => labels 10 to 19 
# splited_array[1][1] => values 10 to 19 

要做到这一点的最佳方法是什么？ 任何帮助将高度赞赏

Answer 1

这里有一个功能更强大的方法

original = [] 
original[0] = %W(aa bb cc dd ee ff gg hh ii jj kk ll mm nn oo pp qq rr ss tt) 
original[1] = %W(01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20) 

result = original.map {|arr| arr.each_slice(10).to_a}.transpose 

 
=> [[["aa", "bb", "cc", "dd", "ee", "ff", "gg", "hh", "ii", "jj"], 
    ["01", "02", "03", "04", "05", "06", "07", "08", "09", "10"]], 
    [["kk", "ll", "mm", "nn", "oo", "pp", "qq", "rr", "ss", "tt"], 
    ["11", "12", "13", "14", "15", "16", "17", "18", "19", "20"]]] 

Answer 2

喜欢的东西：

a1 = (1..10).to_a 
a2 = ("A".."J").to_a 

out = [] 
current = [] 
a1.zip(a2) do |a, b| 
    current << a 
    current << b 

    if current.length >= 10 
    out << current 
    current = [] 
    end 
end 


out << current unless current.empty? 

请注意，有时这些漂亮的函数式编程范式导致尴尬的解决方案。如果“命令式”编程的东西稍长一些，但要清楚得多。