变化
void context = (void)zmq_ctx_new();
到
void *context = (void *)zmq_ctx_new();
而且,我想你的代码,无效的情况下=(无效)zmq_ctx_new()会导致编译错误。
这是我的代码,可以在我的OSX上工作。
gcc -o cli client.c -lzmq
gcc -o srv server.c -lzmq
client.c:
#include <zmq.h>
#include <string.h>
#include <stdio.h>
#include <unistd.h>
int main (void)
{
printf ("Connecting to hello world server…\n");
void *context = (void *)zmq_ctx_new();
void *requester = zmq_socket (context, ZMQ_REQ);
zmq_connect (requester, "tcp://localhost:5555");
int request_nbr;
for (request_nbr = 0; request_nbr != 10; request_nbr++) {
char buffer [10];
char snd[] = "hello";
printf ("Sending Hello %d…\n", request_nbr);
zmq_send (requester, snd, sizeof(snd), 0);
zmq_recv (requester, buffer, 10, 0);
printf ("Received World %d\n", request_nbr);
}
zmq_close (requester);
zmq_ctx_destroy (context);
return 0;
}
server.c:
#include <zmq.h>
#include <stdio.h>
#include <unistd.h>
#include <string.h>
#include <assert.h>
int main (void)
{
// Socket to talk to clients
void *context = zmq_ctx_new();
void *responder = zmq_socket (context, ZMQ_REP);
int rc = zmq_bind (responder, "tcp://*:5555");
assert (rc == 0);
while (1) {
int nrecv;
char buffer [10];
nrecv = zmq_recv (responder, buffer, 10, 0);
printf ("[%d] Received %s\n", nrecv, buffer);
sleep (1); // Do some 'work'
zmq_send (responder, "World", 5, 0);
}
return 0;
}
我的第一个语句:无效的情况下=(无效)zmq_ctx_new();实际上,void * context =(void *)zmq_ctx_new();不知道为什么它没有把*放在那里。无论如何..只是想澄清它 – Kavita
你的调试器说segfault发生在哪里? – Peter
为什么在第一个声明中演员?在C里投这里是没有必要的。如果编译器抱怨没有它,你可能会找到你的问题的原因。 – alk