转换$ note1 = mysql_result（$ result，0，“note_content”）;到mysqli的等效

Question

我有工作得很好以下旧的PHP代码：

<?php 
$query = "SELECT * FROM notes WHERE note_name='Test Note'"; 
$result = mysql_query($query); 

$note1 = mysql_result($result, 0, "note_content"); 
$note2 = mysql_result($result, 1, "note_content"); 

echo "<p>$note1</p> 
<p>$note2</p>" 
?> 

我想将它转化成mysqli的。我做了以下将它转换，但它不工作：

<?php 
$query = "SELECT * FROM notes WHERE note_name='Test Note'"; 
$result = mysqli_query($connect, $query); 

// THIS IS WHERE I AM UNSURE WHAT TO DO??? HERE'S WHAT I TRIED 
$row = mysqli_fetch_array($result, MYSQLI_ASSOC); 

$note1 = $row["note_content"][0]; 
$note2 = $row["note_content"][1]; 

echo "<p>$note1</p> 
<p>$note2</p>" 
?> 

我在做什么错？如果没有，你要取分开的每一行

$all_rows = mysqli_fetch_all($result, MYSQLI_ASSOC); 
$note1 = $all_rows[0]["note_content"]; 
$note2 = $all_rows[1]["note_content"]; 

：

Answer 1

如果您已经安装了mysqlnd驱动程序，你可以做到这一点

$row = mysqli_fetch_assoc($result); 
$note1 = $row["note_content"]; 
$row = mysqli_fetch_assoc($result); 
$note2 = $row["note_content"];