我的屏幕有4个带有tablelayout的选项卡。当我询问SQLite的数据时,该选项卡是由ugt值选择的。Tabview内容重叠
当ugt等于1或2时,现在有问题 - 数据在tab1和tab2之间分开并且正常显示。
但是当ugt等于3或4时,数据显示在所有4个选项卡上!数据与其他数据重叠。
下面是代码:
while (cursor2.moveToNext()) {
int id = cursor2.getInt(cursor2.getColumnIndex(LeaderBase.UID));
String name = cursor2.getString(cursor2.getColumnIndex(LeaderBase.USERNAME));
String money = String.valueOf(cursor2.getLong(cursor2.getColumnIndex(LeaderBase.USERMONEY)));
String speed = String.valueOf(cursor2.getLong(cursor2.getColumnIndex(LeaderBase.USERSPEED)));
String time = String.valueOf(cursor2.getLong(cursor2.getColumnIndex(LeaderBase.USERTIME)));
int ugt = (int)cursor2.getLong(cursor2.getColumnIndex(LeaderBase.UGAMETYPE));
TableRow row = null;
switch(ugt){
case 1:
row = (TableRow)inflater.inflate(R.layout.tablerow, tl1, false);
break;
case 2:
row = (TableRow)inflater.inflate(R.layout.tablerow, tl2, false);
break;
case 3:
row = (TableRow)inflater.inflate(R.layout.tablerow, tl3, false);
break;
case 4:
row = (TableRow)inflater.inflate(R.layout.tablerow, tl4, false);
break;
}
TextView tv1 = (TextView)row.findViewById(R.id.textView1);
TextView tv2 = (TextView)row.findViewById(R.id.textView2);
TextView tv3 = (TextView)row.findViewById(R.id.textView3);
TextView tv4 = (TextView)row.findViewById(R.id.textView4);
tv1.setText(name);
tv2.setText(money);
tv3.setText(time);
tv4.setText(speed);
switch(ugt){
case 1:
tl1.addView(row);
break;
case 2:
tl2.addView(row);
break;
case 3:
tl3.addView(row);
break;
case 4:
tl4.addView(row);
break;
}
}
这里是一个屏幕截图。 感谢您的回答!
完成 - 问题依旧 –
什么是UGT的输出? – Oya
输出正确(1,2,3或4)。有时甚至每个选项卡中的第一行都会重叠移位和混合(我的意思是标题) –