怎样用DATEDIFF函数两个日期之间diffrence动态使用SQL Server 2008

Question

这里是我的表即book_master有以下详细

id  book_nmae  book_cost publish_date 
6 maths   150.0000  1992-08-06 
7 science  120.0000  1992-08-07 
8 gujrati  100.0000  1992-08-08 
9 english  105.0000  1992-08-09 
10 social study 100.0000  1992-08-10 

在这里，我想出版日期1992年8月6日和1992之间diffrence 08-07使用book_name列。

我曾尝试以下条件为sql

SELECT DATEDIFF(DAY,book_master.publish_date,book_master.publish_date) 
from book_master where book_name in('science','maths') 

select DATEDIFF(DAY,book_master.publish_date.book_name('maths'),book_master.publish_date.book_name('science')) 
from book_master 

问候 rajdeep帕尔马

Answer 1

DECLARE @Date1 AS DATETIME 
DECLARE @Date2 AS DATETIME 

SELECT @Date1 = publish_date 
FROM book_master 
WHERE book_name = 'science' 

SELECT @Date2 = publish_date 
FROM book_master 
WHERE book_name = 'maths' 

SELECT DATEDIFF(DAY,@Date1,@Date2) 

Answer 2

另一个解决方案是

SELECT DATEDIFF(DAY,T1.publish_date,T2.publish_date) 
FROM 
    (
    SELECT publish_date 
    FROM book_master 
    WHERE book_name = 'science' 
) T1 
CROSS JOIN 
    (
    SELECT publish_date 
    FROM book_master 
    WHERE book_name = 'maths' 
) T2 

Answer 3

不是按名称搜索书，我会使用的id假设那些id是独一无二的。 解决方案：

DECLARE @MyTable TABLE(
    id INT PRIMARY KEY, -- this PK constraint ensures unique values for this column 
    book_name NVARCHAR(200) NOT NULL, 
    publish_date DATE NOT NULL 
); 

INSERT @MyTable(id,book_name,publish_date) 
VALUES 
(6 ,'maths  ', '1992-08-06'), 
(7 ,'science  ', '1992-08-07'), 
(8 ,'gujrati  ', '1992-08-08'), 
(9 ,'english  ', '1992-08-09'), 
(10,'social study', '1992-08-10'); 

DECLARE @book_id_1 INT, 
     @book_id_2 INT; 
SELECT @book_id_1=6, 
     @book_id_2=7;  

SELECT DATEDIFF(DAY,pvt.[1],pvt.[2]) AS DaysDiff 
FROM(  
    SELECT t.publish_date, 
      ROW_NUMBER() OVER(ORDER BY t.publish_date) AS RowNum 
    FROM @MyTable t 
    WHERE t.id IN (@book_id_1,@book_id_2) 
) x 
PIVOT(MAX(x.publish_date) FOR x.RowNum IN ([1],[2])) pvt; 

结果：

DaysDiff 
----------- 
1