将图片发送到网络服务器

我必须构建一个应将图片从手机发送到网络服务器的应用程序。不幸的是，我真的不知道该怎么做。有人可以帮我吗？将图片发送到网络服务器

2011-03-24 D Brown

可以指定服务器堆栈和可能的API吗？ – 2011-03-24 06:16:34

感谢您回复，Ravi ...它是google apis 1.5，我不确定您的服务器堆栈是什么意思...请问您能解释一下吗？我有点新的android .. – 2011-03-24 06:22:47

@Ravi：他没有说任何异常。 – Mudassir 2011-03-24 06:26:03

做一个HTTP请求，你可以使用DefaultHttpClient类和

HttpClient client = new DefaultHttpClient(); 
HttpPost post = new HttpPost("http://your.site/your/service"); 
// set some headers if needed 
post.addHeader(....); 
// and an eclosed entity to send 
post.setEntity(....); 
// send a request and get response (if needed) 
InputStream responseStream = client.execute(post)..getEntity().getContent();

增加一个实体请求的方法取决于如何远程serivice工作HttpPost类。

来源

2011-03-24 06:19:23 Olegas

感谢Olegas，感谢示例代码。我会尝试一下，看看它是如何发展的。 – 2011-03-24 06:39:59

使用Web服务来实现此任务。

为了在android中使用web服务，请访问此链接。

kSoap2用于从android 设备调用Web服务的库。
Calling simple web service in android.
Calling web service & uploading file through HttpClient
Web Service That Returns An Array of Objects With KSOAP - 对于复杂的对象。
Accessing a JAX-WS web service from Android
How-to: Android as a RESTful Client

来源

2011-03-24 06:19:50

不错..，+1 ..... – Mudassir 2011-03-24 06:27:20

谢谢你一步一步的建议，Shashank。我会试试看看它是如何发展的。 – 2011-03-24 06:28:40

下面是我使用的图像上传到远程服务器，使用原始套接字的代码。 httpclient上的原始套接字的优点是可以显示上传进度条。

声明：该代码大部分主要来自stackoverflow。

/** 
* Asynchronous task to upload file to server 
*/ 
class UploadImageTask extends AsyncTask<File, Integer, Boolean> { 

    /** Upload file to this url */ 
    private static final String UPLOAD_URL = "http://thibault-laptop:8080/report"; 

    /** Send the file with this form name */ 
    private static final String FIELD_FILE = "file"; 
    private static final String FIELD_LATITUDE = "latitude"; 
    private static final String FIELD_LONGITUDE = "longitude"; 

    /** 
    * Prepare activity before upload 
    */ 
    @Override 
    protected void onPreExecute() { 
     super.onPreExecute(); 
     setProgressBarIndeterminateVisibility(true); 
     mConfirm.setEnabled(false); 
     mCancel.setEnabled(false); 
     showDialog(UPLOAD_PROGRESS_DIALOG); 
    } 

    /** 
    * Clean app state after upload is completed 
    */ 
    @Override 
    protected void onPostExecute(Boolean result) { 
     super.onPostExecute(result); 
     setProgressBarIndeterminateVisibility(false); 
     mConfirm.setEnabled(true); 
     mDialog.dismiss(); 

     if (result) { 
      showDialog(UPLOAD_SUCCESS_DIALOG); 
     } else { 
      showDialog(UPLOAD_ERROR_DIALOG); 
     } 
    } 

    @Override 
    protected Boolean doInBackground(File... image) { 
     return doFileUpload(image[0], UPLOAD_URL); 
    } 

    @Override 
    protected void onProgressUpdate(Integer... values) { 
     super.onProgressUpdate(values); 

     if (values[0] == 0) { 
      mDialog.setTitle(getString(R.string.progress_dialog_title_uploading)); 
     } 

     mDialog.setProgress(values[0]); 
    } 

    /** 
    * Upload given file to given url, using raw socket 
    * @see http://stackoverflow.com/questions/4966910/androidhow-to-upload-mp3-file-to-http-server 
    * 
    * @param file The file to upload 
    * @param uploadUrl The uri the file is to be uploaded 
    * 
    * @return boolean true is the upload succeeded 
    */ 
    private boolean doFileUpload(File file, String uploadUrl) { 
     HttpURLConnection conn = null; 
     DataOutputStream dos = null; 
     String lineEnd = "\r\n"; 
     String twoHyphens = "--"; 
     String boundary = "*****"; 
     String separator = twoHyphens + boundary + lineEnd; 
     int bytesRead, bytesAvailable, bufferSize; 
     byte[] buffer; 
     int maxBufferSize = 1 * 1024 * 1024; 
     int sentBytes = 0; 
     long fileSize = file.length(); 

     // The definitive url is of the kind: 
     // http://host/report/latitude,longitude 
     uploadUrl += "/" + mLocation.getLatitude() + "," + mLocation.getLongitude(); 

     // Send request 
     try { 
      // Configure connection 
      URL url = new URL(uploadUrl); 
      conn = (HttpURLConnection) url.openConnection(); 
      conn.setDoInput(true); 
      conn.setDoOutput(true); 
      conn.setUseCaches(false); 
      conn.setRequestMethod("PUT"); 
      conn.setRequestProperty("Connection", "Keep-Alive"); 
      conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary); 
      publishProgress(0); 

      dos = new DataOutputStream(conn.getOutputStream()); 

      // Send location params 
      writeFormField(dos, separator, FIELD_LATITUDE, "" + mLocation.getLatitude()); 
      writeFormField(dos, separator, FIELD_LONGITUDE, "" + mLocation.getLongitude()); 

      // Send multipart headers 
      dos.writeBytes(twoHyphens + boundary + lineEnd); 
      dos.writeBytes("Content-Disposition: form-data; name=\"" + FIELD_FILE + "\";filename=\"" 
        + file.getName() + "\"" + lineEnd); 
      dos.writeBytes(lineEnd); 

      // Read file and create buffer 
      FileInputStream fileInputStream = new FileInputStream(file); 
      bytesAvailable = fileInputStream.available(); 
      bufferSize = Math.min(bytesAvailable, maxBufferSize); 
      buffer = new byte[bufferSize]; 

      // Send file data 
      bytesRead = fileInputStream.read(buffer, 0, bufferSize); 
      while (bytesRead > 0) { 
       // Write buffer to socket 
       dos.write(buffer, 0, bufferSize); 

       // Update progress dialog 
       sentBytes += bufferSize; 
       publishProgress((int)(sentBytes * 100/fileSize)); 

       bytesAvailable = fileInputStream.available(); 
       bufferSize = Math.min(bytesAvailable, maxBufferSize); 
       bytesRead = fileInputStream.read(buffer, 0, bufferSize); 
      } 

      // send multipart form data necesssary after file data 
      dos.writeBytes(lineEnd); 
      dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd); 
      dos.flush(); 
      dos.close(); 
      fileInputStream.close(); 
     } catch (IOException ioe) { 
      Log.e(TAG, "Cannot upload file: " + ioe.getMessage(), ioe); 
      return false; 
     } 

     // Read response 
     try { 
      int responseCode = conn.getResponseCode(); 
      return responseCode == 200; 
     } catch (IOException ioex) { 
      Log.e(TAG, "Upload file failed: " + ioex.getMessage(), ioex); 
      return false; 
     } catch (Exception e) { 
      Log.e(TAG, "Upload file failed: " + e.getMessage(), e); 
      return false; 
     } 
    } 

    private void writeFormField(DataOutputStream dos, String separator, String fieldName, String fieldValue) throws IOException 
    { 
     dos.writeBytes(separator); 
     dos.writeBytes("Content-Disposition: form-data; name=\"" + fieldName + "\"\r\n"); 
     dos.writeBytes("\r\n"); 
     dos.writeBytes(fieldValue); 
     dos.writeBytes("\r\n"); 
    } 
}

要开始上传，请使用以下命令：

new UploadImageTask().execute(new File(imagePath));

来源

2011-04-01 07:12:17

我没有使用Android的一个休息互联网服务和DefaultHttpClient类。要创建一个样本REST Web服务和Apache Tomcat上进行部署，请按照教程Vogella

为了让REST服务接受图像，多内容的类型是在服务器端

@POST 
@Consumes(MediaType.MULTIPART_FORM_DATA) 
@Produces("application/json") 
public String uploadFile(@FormDataParam("image") InputStream uploadedInputStream, 
     @FormDataParam("image") FormDataContentDisposition fileDetail) { 

    String uploadedFileLocation = "e://game/" + fileDetail.getFileName(); 
    boolean response=false; 
    // save it 
    try{ 
     OutputStream out = null; 
     int read = 0; 
     byte[] bytes = new byte[1024]; 
     out = new FileOutputStream(new File(uploadedFileLocation)); 
     while ((read = uploadedInputStream.read(bytes)) != -1) { 
      out.write(bytes, 0, read); 
     } 
     out.flush(); 
     out.close(); 
     return response=true; 
    }catch(IOException e){ 
     e.printStackTrace(); 
    } 
    return response; 

}

需要在Android端发送图像（我在AsyncTask的doInBackground中完成）

  HttpClient httpClient = new DefaultHttpClient(); 
      HttpPost postRequest = new HttpPost("http://"+ip+":8080/MiniJarvisFaceServer/image"); 
      MultipartEntity reqEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE); 
      reqEntity.addPart("image", new FileBody(file)); 
      postRequest.setEntity(reqEntity); 
      ResponseHandler<String> handler = new BasicResponseHandler();   
      String response = httpClient.execute(postRequest,handler); 
      Log.d("Response", response); 
      httpClient.getConnectionManager().shutdown();

来源

2014-08-11 20:28:23 Saumya

请按照本指南进行操作。它在服务器端使用PHP。我使用Android Studio和httpmime.4.3.6，并像魅力一样工作 http://www.androidhive.info/2014/12/android-uploading-camera-image-video-to-server-with-progress-bar/

它也支持视频，它显示了如何响应来自服务器的一些结果。唯一棘手的问题是确保您使用HttClient for Android和正确版本的HttpMime。现在HttpMime 4.4.x没有工作，浪费了我一周的时间。使用4.3.6

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2015-04-11 13:23:25 n00b

将图片发送到网络服务器

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