在两个其他字符之间替换多个相同字符的发生

Question

如何仅在两个其他字符之间存在时才替换字符？即使前后有文字？

举例来说，如果我有一个这样的字符串：

var text = "For text `in between two backticks, replace all #es with *s`. It should `find all such possible matches for #, including multiple ### together`, but shouldn't affect ### outside backticks." 

我所需的输出是：

"For text `in between two backticks, replace all *es with *s`. It should `find all such possible matches for *, including multiple *** together`, but shouldn't affect ### outside backticks." 

我有下面的代码：

text = text.replace(/`(.*?)#(.*?)`/gm, "`$1*$2`"); 

Answer 1

使用一个简单的/`[^`]+`/g正则表达式，它将匹配一个反引号，然后1+字符而不是反引号，然后再一个backti CK，并更换#回调中：

var text = "For text `in between two backticks, replace all #es with *s`. It should `find all such possible matches for #, including multiple ### together`, but shouldn't affect ### outside backticks."; 
 
var res = text.replace(/`[^`]+`/g, function(m) { 
 
    return m.replace(/#/g, '*'); 
 
}); 
 
console.log(res);