得到两个日期之间的月份名称

Question

我必须有两个日期from和to。我想在这两个日期之间得到所有的月份名称。

以下是我的代码

var monthNames = [ "January", "February", "March", "April", "May", "June", 
     "July", "August", "September", "October", "November", "December" ]; 

function diff(from, to) { 
    var datFrom = new Date('1 ' + from); 
    var datTo = new Date('1 ' + to); 
    var arr = monthNames.slice(datFrom.getMonth(), datTo.getMonth() + 1); 
} 

上面的代码适用于以下输入

diff('September 2013', 'December 2013'); 

，但它不适用于本

diff('September 2013', 'February 2014'); 

工作，我怎样才能使它发挥作用？

Answer 1

煤矿是更好：http://jsfiddle.net/kS73f/8/

var monthNames = [ "January", "February", "March", "April", "May", "June", 
     "July", "August", "September", "October", "November", "December" ]; 

function diff(from, to) { 
    var arr = []; 
    var datFrom = new Date('1 ' + from); 
    var datTo = new Date('1 ' + to); 
    var fromYear = datFrom.getFullYear(); 
    var toYear = datTo.getFullYear(); 
    var diffYear = (12 * (toYear - fromYear)) + datTo.getMonth(); 

    for (var i = datFrom.getMonth(); i <= diffYear; i++) { 
     arr.push(monthNames[i%12] + " " + Math.floor(fromYear+(i/12))); 
    }   

    return arr; 
} 

console.log(diff('September 2013', 'March 2014')); 

Answer 2

你将不得不做一个比切片更手动的方法。这里有一个起点，您可以确定如何处理评论中提到的案例。

function diff(from, to) { 
    var result = []; 
    var datFrom = new Date('1 ' + from); 
    var datTo = new Date('1 ' + to); 
    if(datFrom < datTo) { 
     var month = datFrom.getMonth(); 
     var toMonth = datTo.getMonth() + 1 + ((datTo.getYear() - datFrom.getYear())*12); //toMonth adjusted for year 
     for(; month < toMonth; month++) { //Slice around the corner... 
     result.push(monthNames[month % 12]); 
     } 
    } 

    return result; 
} 

diff('September 2013', 'February 2014'); //=["September", "October", "November", "December", "January", "February"] 

Answer 3

var monthNames = [ "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December" ]; 

function diff(from, to) { 
    var datFrom = new Date('1 ' + from); 
    var datTo = new Date('1 ' + to); 
    var arr; 
    if(datFrom > datTo) { 
     return diff(to, from); 
    } 

    var fromYear = datFrom.getFullYear(); 
    var toYear = datTo.getFullYear(); 

    if(fromYear === toYear) { 
     return monthNames.slice(datFrom.getMonth(), datTo.getMonth() + 1); 
    } else { 
     var arr = addYear(monthNames.slice(datFrom.getMonth(), new Date('1 December ' + fromYear)), fromYear); 
     for(var i = 1; i < (toYear - fromYear); i++) { 
     arr = arr.concat(addYear(monthNames, fromYear + i)); 
     } 
     return arr.concat(addYear(monthNames.slice(new Date('1 January ' + fromYear).getMonth(), datTo.getMonth() + 1), toYear)); 
    } 
} 

function addYear(arr, year) { 
    var updatedArr = []; 
    for(var i = 0; i < arr.length; i++) { 
    updatedArr[i] = arr[i] + ' ' + year; 
    } 
    return updatedArr; 
} 

不是试图console.log(diff('September 2013', 'February 2015'))进行测试。

Answer 4

懒回答：

var monthNames = [ "January", "February", "March", "April", "May", "June", 
     "July", "August", "September", "October", "November", "December", 
     "January", "February", "March", "April", "May", "June", 
     "July", "August", "September", "October", "November", "December" ]; 

function diff(from, to) { 
    var mFrom = new Date('1 ' + from).getMonth(); 
    var mTo = new Date('1 ' + to).getMonth(); 
    mTo = mTo < mFrom ? mTo + 12 : mTo; 
    return monthNames.slice(mFrom, mTo + 1); 
} 

alert(diff('September 2013', 'December 2013')); 
alert(diff('September 2013', 'February 2014')); 

Answer 5

以下修改原有的功能尽可能少的，如果这能帮助从理解的角度来看，OP。

function diff(from, to) { 
    var datFrom = new Date('1 ' + from); 
    var datTo = new Date('1 ' + to); 
    var arr = monthNames.slice(datFrom.getMonth(), datTo.getMonth() + 1); 

    if (!arr.length) { 
     arr = monthNames.slice(datFrom.getMonth(), 12); 
     arr = arr.concat(monthNames.slice(0, datTo.getMonth() + 1)); 
    } 

    return arr; 
} 

console.log(diff('December 2013', 'February 2014')); //["September", "October", "November", "December", "January", "February"]