我刚刚发现如何循环基于另一个数组的数组,但是我的问题是,如果第二个数组只是1个对象而不是它的工作正常,但我想使它与两个对象。基于第一个数组的循环PHP数组
这里是如何做的工作,
$shorten = array(
0 => 'ECAR',
1 => 'CCAR',
2 => 'ICAR',
3 => 'SCAR',
4 => 'FCAR',
5 => 'PCAR',
);
$data = array(
'Hertz' => array(
'ECAR' => '49.21',
'CCAR' => '71.04',
'ICAR' => '89.58',
'SCAR' => '100.00',
)
),
'Avis' => array(
'ECAR' => '412.00',
'CCAR' => '347.00',
'ICAR' => '285.00',
'SCAR' => '224.00',
'FCAR' => '165.00',
'PCAR' => '100.00',
)
),
);
// default array as the base
$shorten = array_combine($shorten, array_fill(0, count($shorten), 'n/a'));
foreach($data as &$array) {
// merge to get set members
$array = array_merge($shorten, $array);
}
unset($array);
print_r($data);
一个例子,但我想让它与这一个工作,
$shorten = array(
0 => 'ECAR',
1 => 'CCAR',
2 => 'ICAR',
3 => 'SCAR',
4 => 'FCAR',
5 => 'PCAR',
);
$data = array(
'Hertz' => array(
'NYCT01' => array(
'ECAR' => '49.21',
'CCAR' => '71.04',
'ICAR' => '89.58',
'SCAR' => '100.00',
)
),
'Avis' => array(
'NYCT01' => array(
'ECAR' => '412.00',
'CCAR' => '347.00',
'ICAR' => '285.00',
'SCAR' => '224.00',
'FCAR' => '165.00',
'PCAR' => '100.00',
)
),
);
// default array as the base
$shorten = array_combine($shorten, array_fill(0, count($shorten), 'n/a'));
foreach($data as $firstArray) {
foreach($firstArray as &$array){
// merge to get set members
$array = array_merge($shorten, $array);
}
}
unset($array);
print_r($data);
而这正是我希望它是,
Array
(
[Hertz] => Array
(
[ECAR] => 49.21
[CCAR] => 71.04
[ICAR] => 89.58
[SCAR] => 100.00
[FCAR] => n/a
[PCAR] => n/a
)
[Avis] => Array
(
[ECAR] => 412.00
[CCAR] => 347.00
[ICAR] => 285.00
[SCAR] => 224.00
[FCAR] => 165.00
[PCAR] => 100.00
)
)
$ data [1] [0] [0] = 412.00;这就是你将如何访问数组中的数组等等,如果这就是你的意思,是吗?我真的不明白你的问题。 – Cninroh
请检查阵列我想要它应该是什么,thanx – thegrede
如果您的问题得到解答,请设置[✔接受答案打勾](http://meta.stackexchange.com/q/5234),不要编辑标题。 – mario