从其中的每个单词的位置重新创建一个句子

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我期待开发一个程序，可以识别句子中的单个单词，并用每个单词在列表中的位置替换每个单词。从其中的每个单词的位置重新创建一个句子

例如，有这样一句话：

HELLO I NEED SOME HELP IN PYTHON PLEASE CAN YOU HELP ME IN PYTHON

这包含11个不同的话，我想我的程序重新创建这些11个字在列表中的位置了一句：

1,2,3,4,5,6,7,8,9,10,5,11,6,7

然后我想将这个新列表保存在一个单独的文件中。到目前为止，我只得到了这一点：

#splitting my string to individual words 
my_string = "HELLO I NEED SOME HELP IN PYTHON PLEASE CAN YOU HELP ME IN PYTHON"  
splitted = my_string.split()

来源

2015-10-06 new.teacher

>>> my_string = "HELLO I NEED SOME HELP IN PYTHON PLEASE CAN YOU HELP ME IN PYTHON"  
>>> splitted = my_string.split() 
>>> order = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 5, 11, 6, 7 
>>> new_str = ' '.join(splitted[el] for el in order) 
'I NEED SOME HELP IN PYTHON PLEASE CAN YOU HELP IN ME PYTHON PLEASE'

更新根据您的评论：

您正在寻找index()方法。

my_string = "HELLO I NEED SOME HELP IN PYTHON PLEASE CAN YOU HELP ME IN PYTHON"  
splitted = my_string.split() 
test = "I NEED SOME HELP IN PYTHON PLEASE CAN YOU HELP IN ME PYTHON PLEASE".split() 
print ', '.join(str(splitted.index(el)) for el in test) 

>>> 1, 2, 3, 4, 5, 6, 7, 8, 9, 4, 5, 11, 6, 7

**我们假设有没有重复的话

来源

2015-10-06 13:40:12

我认为数应该是'[1，2，3，4，5，6，7，8，9，10，11，5,7]' – SirParselot

@SirParselot元组或列表中没有区别（这只是常量） –

不，我是指数字的顺序。 – SirParselot

my_string = "HELLO I NEED SOME HELP IN PYTHON PLEASE CAN YOU HELP ME IN PYTHON"  
splitted = my_string.split() 
d = {} 
l=[] 
for i,j in enumerate(splitted): 
    if j in d: 
     l.append(d[j]) 
    else: 
     d[j]=i 
     l.append(i) 
print l 

[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 4, 11, 5, 6]

来源

2015-10-06 13:54:33 SirParselot

非常感谢！这真的帮了我:) :) –

@ new.teacher不要忘记upvote然后标记帮助最多的答案 – SirParselot

试试这个：

sentence= "HELLO I NEED SOME HELP IN PYTHON PLEASE CAN YOU HELP ME IN PYTHON" 
lst = sentence.split() 
lst2= [] 

for i in lst: 
    if i not in lst2: 
     lst2.append(i) 

inp = inputSentence.split() 
output=[] 
for i in inp: 
    print lst2.index(i)+1, 
    output.append(lst2.index(i)+1)

该指数是评估并存储在lst2。您只需将您的输入字符串传递给inputSentence，以便您可以测试此代码。

来源

2015-10-06 14:02:31

尝试：

>>> from collections import OrderedDict 
>>> my_string = "HELLO I NEED SOME HELP IN PYTHON PLEASE CAN YOU HELP ME IN PYTHON" 
>>> splitted = my_string.split() 
>>> key_val = {elem : index + 1 for index, elem in enumerate(list(OrderedDict.fromkeys(splitted)))} 
>>> [key_val[elem] for elem in splitted] 
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 5, 11, 6, 7]

list(OrderedDict.fromkeys(splitted))创建具有splitted只有唯一元素的列表。
key_val是这些独特元素的字典，作为键和它们的索引作为值。

来源

2015-10-06 14:15:19 Praveen

benstring = input ('enter a sentence ') 

print('the sentence is', benstring) 

ben2string = str.split(benstring) 

print('the sentence now looks like this',ben2string) 

x=len(ben2string) 
for i in range(0,x): 
    if x is

来源

2016-01-27 14:05:23 user5847194

请解释！ –

Sentence = input("Enter a sentence!") 
s = Sentence.split() #Splits the numbers/words up so you can see them individually. 
another = [0] 

for count, i in enumerate(s): 
    if s.count(i) < 2: 
     another.append(max(another) + 1) #adds +1 each time a word is used, showing the position of each word. 
    else: 
     another.append(s.index(i) +1) 

another.remove(0) 

print(another) #prints the number that word is in.

来源

2016-09-12 12:03:48 Isiah

从其中的每个单词的位置重新创建一个句子

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