通过jpa加入一个java对象中的两个表

Question

我需要将2个表连接到一个具有某些条件的对象。我有以下几点：

@Entity 
@Table(name = "polling") 
public class Polling extends DomainIdObject { 

    @ManyToOne 
    @JoinColumn(name = "owner_id") 
    private Person owner; 

    @Column(name = "poll_name") 
    private String name; 

    @Column(name = "description") 
    private String description; 

    @ManyToMany(targetEntity = PollingSchedule.class, mappedBy = "polling", fetch = FetchType.EAGER) 
    private List<PollingSchedule> variants; 

    @Column(name = "start_time") 
    private LocalDateTime startTime; 

    @Column(name = "end_time") 
    private LocalDateTime endTime; 

    //getters and setters 

@Entity 
@Table(name = "polling_schedule") 
public class PollingSchedule extends DomainIdObject { 

    @JoinColumn(name = "polling_id") 
    private Polling polling; 

    @Column(name = "poll_var") 
    private String pollingVariant; 

    //gettters and setters 

但是当我执行下面的代码：

Query query = getEntityManager().createNativeQuery("SELECT * FROM polling p WHERE p.id=1", Polling.class); 
List list = query.getResultList(); 
List<PollingSchedule> variants = ((Polling) list.get(0)).getVariants(); 

变种列表是空的。在数据库表看起来如下：

polling 
|id|owner_id|poll_name|description|start_time|end_time| 

polling_schedule 
|id|polling_id|poll_var| 

所以，结果我想要的投票对象仅包含那些PollingVariants，那些在polling_schedule表相应polling_id。

我试过使用Filter，SecondaryTable注解，但它不适合我（或者我错误地使用它）。

我使用hibernate4和spring引导1.5.1

任何人都可以帮助我吗？

Answer 1

我认为Polling和PollingSchedule之间的关系是一对多（非多对多）。既然你需要这些对象之间的双向关系，你应该改变他们是这样的：

Pooling.java

@Entity 
@Table(name = "polling") 
public class Polling extends DomainIdObject { 
    ... 
    @OneToMany(mappedBy="polling") 
    private List<PollingSchedule> variants; 
    ... 
} 

PoolingSchedule.java

@Entity 
@Table(name = "polling_schedule") 
public class PollingSchedule extends DomainIdObject { 

    @ManyToOne 
    @JoinColumn(name = "polling_id") 
    private Polling polling; 
    ... 
}