在MySQL/phpMyAdmin中选择与ID相反的单元格

Question

有人能请我指出正确的方向吗？

鉴于表：

actor_uri_address 
--------------------- 
| ID | URI | Address| 
--------------------- 
| |  |  | 
--------------------- 

actor_full_name_opc 
----------------------------------------------- 
| ID | Given Name | Surname | Outward Postcode| 
----------------------------------------------- 
| |   |   |     | 
----------------------------------------------- 

我想生成包含演员URI，名字，姓氏和生活在名单上的地址相同的演员的地址表（我并不需要提供的地址在查询时间，而不是地址栏中的重复值）在phpMyAdmin上。

到目前为止，下面是我的查询结构。尽管做了所有的努力，但我只能使它运行并返回整个URI，名字，姓氏和地址。我完全停留在如何缩小仅限于住在同一地址的演员。

感谢您提前。

SELECT 
    `actor_uri_address`.`URI`, 
    `actor_full_name_opc`.`Given Name`, 
    `actor_full_name_opc`.`Surname`, 
    `actor_uri_address`.`Address` 
FROM 
    `actor_uri_address` 
LEFT JOIN `actor_full_name_opc` ON `actor_full_name_opc`.`ID` = `actor_uri_address`.`ID` 
GROUP BY 
    `actor_uri_address`.`URI`, 
    `actor_full_name_opc`.`Given Name`, 
    `actor_full_name_opc`.`Surname`, 
    `actor_uri_address`.`Address` 

Answer 1

下面是一个例子使用（希望类似的数据）

CREATE TABLE `customer` (
    `id` int(11) DEFAULT NULL, 
    `version` decimal(10,2) DEFAULT NULL, 
    `title` varchar(20) DEFAULT NULL, 
    `FirstName` varchar(20) DEFAULT NULL, 
    `Middlenames` varchar(20) DEFAULT NULL, 
    `LastName` varchar(20) DEFAULT NULL, 
    `Gender` varchar(4) DEFAULT NULL, 
    `Dob` date DEFAULT NULL, 
    `Dod` date DEFAULT NULL, 
    `Warning_flag` varchar(2) DEFAULT NULL, 
    `Worth` varchar(2) DEFAULT NULL 
) ENGINE=InnoDB DEFAULT CHARSET=latin1 

CREATE TABLE `customer_address` (
    `id` int(11) DEFAULT NULL, 
    `version` decimal(10,2) DEFAULT NULL, 
    `Customer_id` int(11) DEFAULT NULL, 
    `line1` varchar(50) DEFAULT NULL, 
    `line2` varchar(50) DEFAULT NULL, 
    `line3` varchar(50) DEFAULT NULL, 
    `line4` varchar(50) DEFAULT NULL, 
    `line5` varchar(50) DEFAULT NULL, 
    `postcode` varchar(10) DEFAULT NULL 
) ENGINE=InnoDB DEFAULT CHARSET=latin1 

truncate table customer; 
insert into customer values 
(1,1,'Mr','fname1',null,'lname1','m','1990-01-01',null,null,null), 
(2,1,'Mrs','fname1',null,'lname1','f','1990-01-01',null,null,null), 
(3,1,'Mrs','fname1',null,'lname1','f','1990-01-01',null,null,null); 
truncate table customer_address; 
insert into customer_address values 
(1,1,1,'Line1','Line2','Line3','Line4','Line5','pc1'), 
(2,1,2,'Line1','Line2','Line3','Line4','Line5','pc1'), 
(3,1,3,'Line1','Line2','Line3','Line4','Line5','pc2'); 

所以，如果我想找到在同一邮政编码

MariaDB [bank]> select ca.postcode, count(*) obs 
    -> from customer_address ca 
    -> group by ca.postcode ; 
+----------+-----+ 
| postcode | obs | 
+----------+-----+ 
| pc1  | 2 | 
| pc2  | 1 | 
+----------+-----+ 
2 rows in set (0.00 sec) 

的客户数量，但如果我想限制它对那些有1个或更多客户

select ca.postcode, count(*) obs 
from customer_address ca 
group by ca.postcode having count(*) > 1 

现在我知道这是我可以让客户居住在这些邮政编码

MariaDB [bank]> select c.id,c.title, c.firstname, c.lastname,s.obs LivingAtThisPostcode 
    -> from customer c 
    -> join customer_address ca on ca.Customer_id = c.id 
    -> join 
    -> (
    -> select ca.postcode, count(*) obs 
    -> from customer_address ca 
    -> group by ca.postcode having count(*) > 1 
    ->) s on s.postcode = ca.postcode ; 
+------+-------+-----------+----------+----------------------+ 
| id | title | firstname | lastname | LivingAtThisPostcode | 
+------+-------+-----------+----------+----------------------+ 
| 1 | Mr | fname1 | lname1 |     2 | 
| 2 | Mrs | fname1 | lname1 |     2 | 
+------+-------+-----------+----------+----------------------+ 
2 rows in set (0.00 sec)