在网站上登录后显示用户名

Question

我正在设计一个带有登录页面的网站。登录部分和从数据库抓取工作正常。但我想在登录后在主页上显示用户名。我使用session_start（）。但用户名不显示。我在这里查了类似的问题，但没有一个是我的答案。以下是代码： PHP代码：

$email = mysqli_real_escape_string($con,$_POST['user']); 
$pass = mysqli_real_escape_string($con,$_POST['pass']); 
$sel_user = "select * from admins where email='$email' AND password='$pass'"; 
$run_user = mysqli_query($con, $sel_user); 
$check_user = mysqli_num_rows($run_user); 
if($check_user>0) 
{ 
$_SESSION['email']=$email 
echo "<script>window.open('index2.html','_self')</script>"; 
} 
else { 
echo "<script>alert('Email or password is not correct, try again!')</script>"; 
} 

index2.html：

<?php 
     session_start(); 
?> 
    <div class="inline-block"> 
           <h5 class="no-margin"> Welcome </h5> 
           <h4 class="no-margin"> <?php echo $_SESSION['email']; ?> </h4> 
           <a class="btn user-options sb_toggle"> 
            <i class="fa fa-cog"></i> 
           </a> 
          </div> 

Answer 1

尝试以下代码：

第一代码：

session_start(); 
$email = mysqli_real_escape_string($con,$_POST['user']); 
$pass = mysqli_real_escape_string($con,$_POST['pass']); 
$sel_user = "select * from admins where email='$email' AND password='$pass'"; 
$run_user = mysqli_query($con, $sel_user); 
$check_user = mysqli_num_rows($run_user); 
if($check_user>0) 
{ 
    $_SESSION['email']=$email 
    echo "<script>window.open('index2.html','_self')</script>"; 
} 
else { 
    echo "<script>alert('Email or password is not correct, try again!')</script>"; 
} 

index2.php：

<?php session_start(); ?> 
<div class="inline-block"> 
    <h5 class="no-margin"> Welcome </h5> 
    <h4 class="no-margin"> <?php echo $_SESSION['email']; ?> </h4> 
    <a class="btn user-options sb_toggle"> 
     <i class="fa fa-cog"></i> 
    </a> 
</div> 

它应该工作。