我在函数中传递IplImage *参数时遇到问题。这是一个学校项目,不幸的是我不应该编辑文件来调用我的过滤器函数。在主,图像带来了作为命令行参数,那么这一份拷贝并传递给正确的过滤器功能,因为这样:传递IplImage *功能,原始不更新
IplImage * floating = cvCreateImage (cvSize (img->width, img->height), IPL_DEPTH_32F, 3);
cvConvertScale (img, floating, 1/255., 0);
IplImage * filtered;
switch (filter.ImageFormat)
{
case YUV24:
filtered = cvCreateImage (cvSize (floating->width, floating->height), IPL_DEPTH_32F, 3);
cvCvtColor (floating, filtered, CV_BGR2YCrCb);
break;
case BGR24:
filtered = cvCloneImage (floating);
break;
case Gray:
filtered = cvCreateImage (cvSize (floating->width, floating->height), IPL_DEPTH_32F, 1);
cvCvtColor (floating, filtered, CV_BGR2GRAY);
break;
}
cvNamedWindow ("original", CV_WINDOW_AUTOSIZE);
cvShowImage ("original", img);
filter.ImageFilter (filtered, p);
if (filter.ImageFormat == YUV24)
{
cvCvtColor (filtered, filtered, CV_YCrCb2BGR);
}
cvNamedWindow (filterName.c_str(), CV_WINDOW_AUTOSIZE);
cvShowImage (filterName.c_str(), filtered);
这里是我的一个过滤器的代码:
void median (IplImage * image, int k){
cout << "image address: " << &image << endl;
Mat matImage(image); //convert IplImage to Mat for work
vector<Mat> bgr_channels; //vector to hold each channel
int i,j,m,n; //row/column indeces
int kernelSize = (2*k+1)*(2*k+1);
vector<float> vals(kernelSize); //kernelSized vector to hold all values of image
//within kernel centered at a given pixel
int vecIndex = 0; //then sorted to get the median
int chanIndex = 0; //index used to for each channel
//add padding to account for border issues with convolution
copyMakeBorder(matImage, matImage, k, k, k, k, BORDER_REPLICATE);
//split channes to do work on individual channels
split(matImage, bgr_channels);
for(chanIndex=0; chanIndex < matImage.channels(); chanIndex++){
//outer loop for scanning entire image
for(i=k; i<matImage.rows-k; i++)/*image row index*/{
for(j=k; j<matImage.cols-k; j++)/*image column index*/{
//inner loop for scanning image only in kernel boundaries
vecIndex = 0; //reset vecIndex at start of each kernel loop
for(m=i-k; m<(i+k+1); m++)/*kernel row index*/{
for(n=j-k; n<(j+k+1); n++)/*kernel column index*/{
vals[vecIndex++] = bgr_channels[chanIndex].at<float>(m,n);
}
}
insertionSort(vals, 0, vals.size()-1); //insertion sort from CSCI362 text, see references
bgr_channels[chanIndex].at<float>(i,j) = vals[vals.size()/2]; //new value chosen from middle element //of sorted vector
}
}
}
merge(bgr_channels, matImage); //merge channels together
imshow("Median: Mat", matImage); //left this in becuase the original doesn't seem to get modified
//when converting the Mat back to an IplImage
image = cvCloneImage(&(IplImage)matImage); //convert backto IplImage for DesktopMain
}
问题是,显示在main中的过滤图像并不反映实际图像。它只显示原始图像。当我输出将Mat样式图像matImage放入我的过滤器函数中时,它将显示已过滤的图像。立即在我转换回IplImage并将IplImage *输入参数设置为等于转换后的过滤版本后立即生效。但这些更改不反映主要功能中显示的图像。
这使得很难创建一些我的其他过滤器,如高斯和索贝尔,因为这些过滤器本身在进行操作之前调用其他函数,并且我没有获取编辑的数据。在如何编辑传递的IplImage *变量时是否存在缺少的内容?
非常感谢您的帮助!
是的,这真是棒极了。最初有一些问题,因为我已经填充了matImage的边界,但剥离了它并且工作得很好。 出于好奇,需要了解,上述两者有何区别。两者似乎都在IplImage *图像上运行。如果我在cvCloneImage调用后执行cvShowImage(“image”,image),我会看到过滤的版本。为什么不会像cvCopy那样影响主图像?非常感谢你的帮助! – jrpharis 2013-02-10 17:39:01
@JoshPharis:您正在通过值传递参数,即将指针的*副本*传递给该函数。这意味着你可以改变*指针指向的内容*,并且该变异可以在函数之外看到,但是如果给参数赋予一个全新的值,那么你只是修改了传递给该函数的副本。C中的所有参数都是按值传递的,而在C++中,当您使用类似的东西时,您可以通过引用传递; void foo(SomeType & arg);' – 2013-02-11 00:52:15