为循环越过跳过javascript

我想做一个简单的JavaScript猜谜游戏，我的for循环不断跳过！这里是越来越跳过我的代码的一部分：为循环越过跳过javascript

for (i = 0; i === tries; i += 1) { 
    isSkipped = false; 
    var guessedNumber = prompt("Guess your number now."); 

    console.log("User guessed number " + guessedNumber); 

    //check if number is correct 
    if (guessedNumber === numberToGuess) { 
     confirm("Hooray, you have guessed the number!"); 
     break; 
    } else if (guessedNumber > numberToGuess) { 
     confirm("A little too high..."); 
    } else { 
     confirm("A little too low..."); 
    } 
}

，这里是完整的代码：

//declaring variables 
var numberToGuess; 
var tries; 
var i; 
var isSkipped = true; 

var confirmPlay = confirm("Are you ready to play lobuo's guessing game? The number for you to guess will be a number ranging from 1 to 25."); //does the user want to play? 

if (confirmPlay === true) { 
    console.log("User wants to play"); 
} else { 
    window.location = "http://lobuo.github.io/pages/experiments.html"; 
} //if user wants to play, let them play, else go to website homepage 

numberToGuess = Math.floor((Math.random() * 25) + 1); //sets computer-generated number 

tries = prompt("How many tries would you like?"); //gets amount of tries 
tries = Math.floor(tries); //converts amount of tries to integer from string 

for (i = 0; i === tries; i += 1) { 
    isSkipped = false; 
    var guessedNumber = prompt("Guess your number now."); 

    console.log("User guessed number " + guessedNumber); 

    //check if number is correct 
    if (guessedNumber === numberToGuess) { 
     confirm("Hooray, you have guessed the number!"); 
     break; 
    } else if (guessedNumber > numberToGuess) { 
     confirm("A little too high..."); 
    } else { 
     confirm("A little too low..."); 
    } 
} 

if (isSkipped === true) { 
    console.log("Oh no! The for loop has been skipped!"); 
}

如果您需要任何进一步的细节，只问。

来源

2014-02-23 lobuo

什么，这是对'i + = 0' ??? – elclanrs

oops ...我修正了这个问题，但还是一无所获......它应该是i + = 1 – lobuo

只需使用i ++;除了'我===试''不好迭代！ – goseo

当你写：

for (i = 0; i === tries; i += 0) {

循环，只要重复条件i === tries为真。例如，如果tries为3，则在第一次迭代中该条件不成立，并且循环立即结束。

你应该写：

for (i = 0; i < tries; i++) {

来源

2014-02-23 06:55:54 Barmar

这有帮助。感谢：D – lobuo

此外，您需要使用parseInt()功能在用户的输入。

var guessedNumber = parseInt(prompt("Guess your number now."), 10);

代替

var guessedNumber = prompt("Guess your number now.");

来源

2014-02-23 06:53:42

为什么downvote，他检查类型也'猜测数字=== numberToGuess'？ –

@SumanBogati因为类型无关紧要，因为无论'Math.floor'后面的数字如何，它都是数字。 –

@ Qantas94Heavy - ？ –

不应该的是这样的？：

for (i = 0; i < tries; i += 1) {

来源

2014-02-23 06:55:26 juvian

您可能想解释两者之间的区别，并提供编辑的代码。 –

哎呀...没有注意到你我做了<尝试。这解决了它。谢谢：D – lobuo

真的吗？我进入了3次尝试，它的工作 – juvian

为循环越过跳过javascript

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