1
我正在开发一个新网站。我已经编写了很多，但没有像这个一样先进。 我有一个HTML文件，这是主页。现在，我正在通过ajax更改页面的内容。一切正常。所以当我点击时，可以说，“主页”菜单，它调用该函数，并获取其中包含内容的另一个HTML文件。Javascript将不会执行
在我的主HTML我有这样的：
<html>
<head>
<title>
Estancia
</title>
<link rel="stylesheet" href="css/stylesheet.css"/>
<link rel="stylesheet" href="webfont/webFontStylesheet.css" type="text/css" charset="utf-8"/>
<script type="text/javascript" src="js/ajax.js"></script>
</head>
<body onLoad = "javascript:home()">
<div id = "bodyLeft">
<!-- This is just a sideskirt -->
</div>
<div id = "bodyRight">
<!-- This is just a sideskirt -->
</div>
<div id = "header">
<h1>
Estancia
</h1>
</div>
<div id = "footer">
<h5>
Copyright© 2013
</h5>
</div>
<div id = "background">
<!-- This is just the background color -->
</div>
<div id = "scrollCover">
<!-- Used to cover the scrolled content -->
</div>
<div id = "body">
</div>
<div id = "content">
If you see this then the page did not load correctly. Try reloading the page. If problem persists, try reinstalling the Mozilla Firefox Browser. <br/><br/> Error: Javascript may not be working. <br/> Fix: Enable Javascript in your browser.
</div>
<div id = "menu">
<div id = "home" onClick="javascript:home()">
<a href = "#"> Home </a>
</div>
<div id = "information">
<a href = "#"> Information </a>
<span id = "aboutDrop">
<a class = "about" href="#" onClick = "javascript:about()"> About </a>
<br/>
<a class = "map" href="#" onClick = "javascript:map()"> Map </a>
</span>
</div>
<div id = "history" onClick = "javascript:history()">
<a href = "#"> History </a>
</div>
<div id = "pictureGallary">
<a href = "#"> Picture Gallary </a>
<span id = "pictureGalleryDrop">
<a class = "ef" href = "#" onClick = "javascript:estanciaFarm()"> Estancia Farm </a>
<br/>
<a class = "ca" href = "#" onClick = "javascript:cattle()"> Cattle </a>
<br/>
<a class = "ga"href = "#" onClick = "javascript:game()"> Game </a>
<br/>
<a class = "go" href = "#" onClick = "javascript:goats()"> Goats </a>
<br/>
<a class = "sh" href = "#" onClick = "javascript:sheep()"> Sheep </a>
</span>
</div>
</div>
</body>
这里没有问题......当我点击它正确加载。 所以，点击首页的时候，它改变通过AJAX这样的内容：
var xmlhttp = new XMLHttpRequest();
var path;
var div;
function home()
{
path = "html/home.html";
div = "content";
AJAX(path, div);
}
function AJAX(path, div)
{
xmlhttp.open("GET", path, false);
xmlhttp.send();
if (xmlhttp.readyState == 4)
{
document.getElementById(div).innerHTML = xmlhttp.responseText;
}
}
正如你可以看到它加载另一个HTML文件上的内容。 所以，这里是HTML文件的代码：
<html>
<head>
<link rel="stylesheet" href="css/homeMenu.css"/>
<script type="text/javascript" src="js/javascript.js"></script>
</head>
<body>
<div id = "slideshow">
<div id = "first">
<img id = "a1" src = "images/home/img1_e.jpg"/>
<img id = "a2" src = "images/home/img2_e.jpg"/>
<img id = "a3" src = "images/home/img3_e.jpg"/>
<img id = "a4" src = "images/home/img4_e.jpg"/>
</div>
<div id = "second">
<img id = "b4" src = "images/home/img4_e.jpg"/>
<img id = "b1" src = "images/home/img1_e.jpg"/>
<img id = "b2" src = "images/home/img2_e.jpg"/>
<img id = "b3" src = "images/home/img3_e.jpg"/>
</div>
<div id = "third">
<img id = "c3" src = "images/home/img3_e.jpg"/>
<img id = "c4" src = "images/home/img4_e.jpg"/>
<img id = "c1" src = "images/home/img1_e.jpg"/>
<img id = "c2" src = "images/home/img2_e.jpg"/>
</div>
<div id = "fourth">
<img id = "d2" src = "images/home/img2_e.jpg"/>
<img id = "d3" src = "images/home/img3_e.jpg"/>
<img id = "d4" src = "images/home/img4_e.jpg"/>
<img id = "d1" src = "images/home/img1_e.jpg"/>
</div>
</div>
</body>
当我加载在其自己的这个HTML文件，它工作正常。我需要改变的是在每个图像路径的开始处添加“../”。我相信你会知道为什么。快速描述是，如果它在它自己，它如果在另一个文件，所以它需要返回一次。当它通过ajax加载到另一个主要的html中时，它在每个文件的外面并进入它。好，那很明显。
问题......我唯一面临的问题是，当我自己加载home.html文件时，它像一块蛋糕一样执行它的JavaScript。
但是，当它加载到主html中，它不起作用。它没有办法执行。我试过内部JavaScript，但它仍然不工作。
这里的JavaScript：
var useBSNns;
if (useBSNns)
{
if (typeof(bsn) == "undefined")
bsn = {}
var _bsn = bsn;
}
else
{
var _bsn = this;
}
_bsn.Crossfader = function (divs, fadetime, delay)
{
this.nAct = -1;
this.aDivs = divs;
for (var i=0;i<divs.length;i++)
{
document.getElementById(divs[i]).style.opacity = 0;
document.getElementById(divs[i]).style.position = "absolute";
document.getElementById(divs[i]).style.filter = "alpha(opacity=0)";
document.getElementById(divs[i]).style.visibility = "hidden";
}
this.nDur = fadetime;
this.nDelay = delay;
this._newfade();
}
_bsn.Crossfader.prototype._newfade = function()
{
if (this.nID1)
clearInterval(this.nID1);
this.nOldAct = this.nAct;
this.nAct++;
if (!this.aDivs[this.nAct]) this.nAct = 0;
if (this.nAct == this.nOldAct)
return false;
document.getElementById(this.aDivs[this.nAct]).style.visibility = "visible";
this.nInt = 50;
this.nTime = 0;
var p=this;
this.nID2 = setInterval(function() { p._fade() }, this.nInt);
}
_bsn.Crossfader.prototype._fade = function()
{
this.nTime += this.nInt;
var ieop = Math.round(this._easeInOut(this.nTime, 0, 1, this.nDur) * 100);
var op = ieop/100;
document.getElementById(this.aDivs[this.nAct]).style.opacity = op;
document.getElementById(this.aDivs[this.nAct]).style.filter = "alpha(opacity="+ieop+")";
if (this.nOldAct > -1)
{
document.getElementById(this.aDivs[this.nOldAct]).style.opacity = 1 - op;
document.getElementById(this.aDivs[this.nOldAct]).style.filter = "alpha(opacity="+(100 - ieop)+")";
}
if (this.nTime == this.nDur)
{
clearInterval(this.nID2);
if (this.nOldAct > -1)
document.getElementById(this.aDivs[this.nOldAct]).style.visibility = "hidden";
var p=this;
this.nID1 = setInterval(function() { p._newfade() }, this.nDelay);
}
}
_bsn.Crossfader.prototype._easeInOut = function(t,b,c,d)
{
return c/2 * (1 - Math.cos(Math.PI*t/d)) + b;
}
请，什么错误，它不希望在其home.html的被装载到主HTML来执行，但是当home.html的是在其自己的IT执行作品？
你看的JavaScript错误日志/控制台？ – 2013-01-06 17:02:02
这听起来像你失去了你的事件处理程序，因为你正在用Ajax重新加载页面的一部分。你的ajax请求是否覆盖了所有内容？ – TommyBs
是的，我认为它会覆盖所有的东西，因为当我点击另一个菜单项时，它会带走所有内容，并用内容替换整个div，让我们来说说，使用ajax将其加载到该div中的about.html文件。 –