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我被困在解析下面的XML中。更改XML文件中的节点和属性文本
<?xml version="1.0" encoding="UTF-8"?>
<Provisioning xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Request>
<Header>
<Command>Create</Command>
<EntityIdentifiers>
<Identifier Type="CosName" Value="Super_Super"/>
</EntityIdentifiers>
<EntityName>COS</EntityName>
</Header>
<Data>
<COS>
<ServiceLevels>
<ServiceLevel>
<ServiceName>MMS</ServiceName>
<ServiceLevelName>Super user</ServiceLevelName>
</ServiceLevel>
<ServiceLevel>
<ServiceName>General</ServiceName>
<ServiceLevelName>Super user</ServiceLevelName>
</ServiceLevel>
<ServiceLevel>
<ServiceName>MMBOX</ServiceName>
<ServiceLevelName>Super user</ServiceLevelName>
</ServiceLevel>
</ServiceLevels>
<CosName>Super_Super</CosName>
</COS>
</Data>
</Request>
</Provisioning>
我需要将“标识符”标签“类型”和“值”替换为其他各自的值。并且还要更改“ServiceLevel”下的所有节点值。
Set xmlDoc = CreateObject("Microsoft.XMLDOM")
xmlDoc.Async = "false"
xmlDoc.Load("C:\1.xml")
Set nodeXML = xmlDoc.getElementsByTagName("Identifier")
Set node = nodeXML.item(0)
MsgBox node.Text
VB脚本不是VB .NET。请采用您的标签。 –
想要这样的https://technet.microsoft.com/en-us/magazine/2008.02.heyscriptingguy.aspx ?? – user5612655