如何解析复杂的XML数据

Question

嗨，大家好我有我有以下的XML解析XML问题具有解析，但我很困惑，如何解析this.I有folow中this

<Root> 
<Category id="1" name="Live" subcategories="6"> 
<SubCategory id="1" name="Entertenment" subcategories="0"/> 
<SubCategory id="2" name="Movies" subcategories="0"/> 
<SubCategory id="3" name="Musics" subcategories="0"/> 
<SubCategory id="4" name="Regional" subcategories="0"/> 
<SubCategory id="5" name="Devotional" subcategories="0"/> 
<SubCategory id="6" name="News" subcategories="4"> 
<ChildCategory id="1" name="International" subcategories="0"/> 
<ChildCategory id="2" name="Politic" subcategories="0"/> 
<ChildCategory id="3" name="Movies" subcategories="0"/> 
<ChildCategory id="4" name="Celeberities" subcategories="0"/> 
</SubCategory></Category> 
</Root> 

如果有任何解决方案请给我建议。

Answer 1

这是从XML解析的代码示例。 首先你创造一个数据库从XML解析存储数据... 只是试试吧..

dh.delete(Exampl.TABLE, null, null); 
    try { 
     DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance(); 
     DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder(); 
     Document doc = docBuilder.parse (istream); 
    doc.getDocumentElement().normalize(); 
    System.out.println ("Root element of the doc is " + 
     doc.getDocumentElement().getNodeName()); 
    NodeList dblist = doc.getElementsByTagName("database"); 
    Element e = (Element) dblist.item(0); 
    NodeList tab = e.getElementsByTagName("table"); 
    System.out.println(tab.getLength() + " Tabels"); 

    for(int k=0;k<tab.getLength();k++) { 

     Element el = (Element) tab.item(k); 
     NodeList col = el.getElementsByTagName("column"); 

     System.out.println("ID is "); 
     System.out.println(); 
     System.out.println(el.getElementsByTagName("column").item(0).getTextContent()); 
     System.out.println(el.getElementsByTagName("column").item(1).getTextContent()); 

     Category .add(el.getElementsByTagName("column").item(0).getTextContent()); 
     subCategory .add(el.getElementsByTagName("column").item(1).getTextContent()); 


    } 


}catch (Exception err) { 
    err.printStackTrace(); 
} 

    for (int j = 0; j < (Category .size()); j++) { 
     ContentValues questionValues = new ContentValues(); 
     System.out.println(Category .get(j)); 
     questionValues.put("Category ", Category .get(j)); 
     questionValues.put("subCategory ", subCategory .get(j)); 


     dh.insert(Example.TABLE, null, 
       questionValues); 

    } 


} 

Answer 2

我遇到了同样的问题，我使用XMLPullParser。您可以通过一个节点&解析XML单店他们的HashMap &如果有相同的标签来，你可以将它们存储在矢量

Answer 3

使用XMLPullParser。示例代码是解析rss内容。

 try { 
       // Standard code to make an HTTP connection. 
       URL url = new URL(RSS_URL); 
       URLConnection connection = url.openConnection(); 
       connection.setRequestProperty("User-agent", "Mozilla/4.0"); 
       connection.setConnectTimeout(20000); 
       connection.connect(); 
       InputStream in = connection.getInputStream(); 

       XmlPullParserFactory factory = XmlPullParserFactory.newInstance(); 
       factory.setNamespaceAware(true); 
       XmlPullParser xpp = factory.newPullParser(); 
       xpp.setInput(in, null); 

       int eventType; 
       String title = ""; 
       String link = ""; 
       String description = ""; 
       String pubDate = ""; 
       eventType = xpp.getEventType(); 
       while (eventType != XmlPullParser.END_DOCUMENT) { 
        if (eventType == XmlPullParser.START_TAG) { 
         String tag = xpp.getName(); 
         if (tag.equals("item")) { 
          title = link = description = ""; 
         } else if (tag.equals("title")) { 
          xpp.next(); 
          title = xpp.getText(); 
         } else if (tag.equals("link")) { 
          xpp.next(); 
          link = xpp.getText(); 
         } else if (tag.equals("description")) { 
          xpp.next(); 
          description = xpp.getText(); 
         } else if (tag.equals("pubDate")) { 
          xpp.next(); 
          pubDate = xpp.getText(); 
         } 
        } else if (eventType == XmlPullParser.END_TAG) { 
         String tag = xpp.getName(); 
         if (tag.equals("item")) { 
          description = " " 
            + description.replaceAll("<a target.*<br>", ""); 
          RssItem item = new RssItem(); 
          item.mTitle = title; 
          item.mUrl = link; 
          item.mDescription = description; 
          item.mPubDate = pubDate; 
          item.mMD5 = MD5.getMD5(link.getBytes()); 

             runOnUiThread(new DataInsert(item)); 
         } 
        } 
        eventType = xpp.next(); 
       } 
      } catch (Exception e) { 
       Log.i(" RssReaderView ", e.getMessage()); 
       e.printStackTrace(); 
      } 

Answer 4

检查使用该

public class MyXmlHandler extends DefaultHandler{ 

    public void startElement(String uri, String localName, String qName, 
      Attributes attributes) throws SAXException { 
     if(qName.equalsIgnoreCase("Category")){ 
        // do something 
      String id = attributes.getValue("id"))); 
String name = attributes.getValue("Name"))); 
String subcategories = attributes.getValue("subcategories"))); 

     }else if(qName.equalsIgnoreCase("SubCategory")){ 
       // do something 
      String id = attributes.getValue("id"))); 
String name = attributes.getValue("Name"))); 
String subcategories = attributes.getValue("subcategories"))); 
     }else if(qName.equalsIgnoreCase("ChildCategory")){ 
       // do something 
      String id = attributes.getValue("id"))); 
String name = attributes.getValue("Name"))); 
String subcategories = attributes.getValue("subcategories"))); 
     } 

    } 


    public void endElement(String uri, String localName, String qName) 
    throws SAXException { 
     if(qName.equalsIgnoreCase("Category ")){ 
      //Do something 
     }if(qName.equalsIgnoreCase("subCategory ")){ 
      //Do something 
     } 
if(qName.equalsIgnoreCase("ChildCategory ")){ 
      //Do something 
     } 
    } 
    /* (non-Javadoc) 
    * @see org.xml.sax.helpers.DefaultHandler#characters(char[], int, int) 
    */ 
    public void characters(char[] ch, int start, int length) 
      throws SAXException { 
     // TODO Auto-generated method stub 
    } 

} 

Answer 5

试试这个

 public class MyXmlHandler extends DefaultHandler{ 


boolean isCategory, isChildCategory,isSubCategory = false; 

    public void startElement(String uri, String localName, String qName, 
      Attributes attributes) throws SAXException { 

     if(qName.equalsIgnoreCase("Category")) 
      { 
      isCategory = true; 
      String id = attributes.getValue("id"); 

     }else if(qName.equalsIgnoreCase("SubCategory"){ 
        isSubCategory =true; 
      String id = attributes.getValue("id"); 


     }else if(qName.equalsIgnoreCase("ChildCategory")){ 
       // do something 
      String id = attributes.getValue("id"); 
      isChildCategory =false; 
      } 


    } 


    public void endElement(String uri, String localName, String qName) 
    throws SAXException { 
     if(qName.equalsIgnoreCase("Category ")){ 
      isCategory = false; 
     }if(qName.equalsIgnoreCase("subCategory ")){ 
      isSubCategory = false; 
     } 
if(qName.equalsIgnoreCase("ChildCategory ")){ 
      isChildCategory =false; 
     } 
    } 
    /* (non-Javadoc) 
    * @see org.xml.sax.helpers.DefaultHandler#characters(char[], int, int) 
    */ 
    public void characters(char[] ch, int start, int length) 
      throws SAXException { 
      String value = new String(ch,start,length); 
     if(isCategory) 
     { 
      String str = value; 
     } 

     if(isSubCategory) 
     { 
      String str1 = value; 
     } 
    } 

} 
//////// 
//TO call MyXmlHandler 
try{ 
      SAXParserFactory spf=SAXParserFactory.newInstance(); 
      SAXParser sp=spf.newSAXParser(); 
      XMLReader xr=sp.getXMLReader(); 
      MyXmlHandler datahandler=new MyXmlHandler(); 
      xr.setContentHandler(datahandler); 


      xr.parse(new InputSource("url")); 

      }catch(Exception e) 
      { 
       Log.e("SAX XML", "i solve error"); 
      } 

Answer 6

您可以使用简单的XML解析器库，这是很容易在Android中使用。你必须在你的代码中创建相关的类和对象。你可以按照链接了解它 http://robertmassaioli.wordpress.com/2011/04/21/simple-xml-in-android-1-5-and-up/