如何在android中创建一个findAll（）方法

Question

如何在android中创建一个findAll（）？我已经尝试过，但我无法实现;

公共列表的findAll（）{ 光标C = mDb.rawQuery（+ TABLE_NAME “” “” “从选择*”）; }

这里是Medicament.java

public class Medicament { 
    private long id; 
    private String nom; 
    private String fabriquant; 
    private String pharmacie; 
    private String description; 
    private float prix; 

    public Medicament(long id, String nom, String fabriquant, String pharmacie, String description, float prix) { 
     super(); 
     this.id = id; 
     this.nom = nom; 
     this.fabriquant = fabriquant; 
     this.pharmacie = pharmacie; 
     this.description = description; 
     this.prix = prix; 
    } 

    public long getId() { 
     return id; 
    } 

    public void setId(long id) { 
     this.id = id; 
    } 

    public String getNom() { 
     return nom; 
    } 

    public void setNom(String nom) { 
     this.nom = nom; 
    } 

    public String getFabriquant() { 
     return fabriquant; 
    } 

    public void setFabriquant(String fabriquant) { 
     this.fabriquant = fabriquant; 
    } 

    public String getPharmacie() { 
     return pharmacie; 
    } 

    public void setPharmacie(String pharmacie) { 
     this.pharmacie = pharmacie; 
    } 

    public String getDescription() { 
     return description; 
    } 

    public void setDescription(String description) { 
     this.description = description; 
    } 

    public float getPrix() { 
     return prix; 
    } 

    public void setPrix(float prix) { 
     this.prix = prix; 
    } } 

编辑：请不要忘记了这一步。

在此先感谢。

Answer 1

尝试somethiing一样，在你的SQLiteOpenHelper：

public List<Medicament> findAll() { 
    List<Medicament> medicaments = new ArrayList<Medicament>(); 
    SQLiteDatabase db = this.getWritableDatabase(); 
    Cursor cursor = db.rawQuery("SELECT * FROM " + TABLE_NAME,null); 
    if (cursor.moveToFirst()) { 
     do { 
      Medicament medicament = new Medicament(); 

      /*fill here medicament object with values from row, 
      cursor.getString(0) = id value, cursor.getString(1) etc... 
      for example medicament.setName(cursor.getString(1))*/ 

      medicaments.add(medicament); 

     } 
     while (cursor.moveToNext()); 
    } 
    return medicaments; 
} 

编辑：

记住正确的使用方法，值类型的细胞， Integer的示例值使用cursor.getInt(COLUMN_NUMBER)，对于Stringcursor.getString(COLUMN_NUMBER) e tc。

Answer 2

做这样

Cursor c = mDb.rawQuery("select * from " + TABLE_NAME,null);