嗨,我试图转换此函数,我写入汇编代码(SPARC弧),但不断收到分段错误(核心转储)错误。该函数应该将字符串转换为长整型值。我知道我正确地完成了C函数,因为我测试了它并且它通过了所有的测试。这是我试图转换的C函数。将C函数转换为程序集
long strToLong(char *str, int base)
{
char *endptr;
errno = 0;
long num;
num = strtol(str, &endptr, base);
char holder[BUFSIZ];
/*if *endptr isn't '\0' then strtol didn't get to the end of the string
*so it wasn't a valid integer*/
if(*endptr != '\0')
{
(void)fprintf(stderr, "\n\t""'%s'" " is not an integer\n", str);
return 0;
}
/*if errno isn't 0 then an error occured so print out an error message*/
else if(errno != 0)
{
(void)snprintf(holder, BUFSIZ,"\n\tConverting \"%s\" base \"%d\"\n caused an ", str, base);
perror(holder);
return 0;
}
/*if no errors, then it was a valid integer so return the integer*/
return num;
}
这是我写的汇编代码。
.global strToULong
.section ".data"
fmt1: .asciz "%s is not an integer\n" !ascii format
fmt2:
.asciz "Converting %s base %d\n" !ascii format
.section ".text"
strToULong:
save %sp, -(92 + 1028) & -8, %sp
add %fp, -4, %o1
mov %i0, %o0
mov %i2, %o2
call strtol
nop
mov %o0, %l0
ld [%fp - 4], %l1
ldub [%l1], %l1
cmp %l1, %g0
be errno
nop
set stdError, %o0
ld [%o0], %o0
set fmt1, %o1
mov %i0, %o2
call fprintf, 3
nop
errno:
mov %l0, %i0
set errno, %l2
ld [%l2], %l2
cmp %l2, %g0
be return
nop
add %fp, -1028, %o0
mov 1024, %o1
set fmt2, %o2
mov %i0, %o3
mov %i1, %o4
call snprintf
nop
add %fp, -1028, %o0
call perror
nop
mov 0, %i0
return:
ret
restore
我调试了程序,当我调用strtol函数时出现seg错误。林不知道我做错了什么,我想我正确地传递参数,但我仍然得到这个错误。哦,在我的主要我有一些声明像FILE * StdError = stderr将stderr作为参数传递给fprintf。
任何帮助将appriciated。
您是否尝试转储由C编译器生成的代码? –
nvm,我其实不太明白你的意思。 –
objdump -d yourcbinary应该给你编译器生成的程序集 – dbrank0