反序列化json数据c＃

我想反序列化由Telegram Bot API收到的JSON响应的getUpdate()方法。反序列化json数据c＃

JSON数据：

{ 
    "ok": true, 
    "result": [ 
    { 
     "update_id": 920493886, 
     "message": { 
     "message_id": 123, 
     "from": { 
      "id": 219633031, 
      "first_name": "Shreeeeeee", 
      "username": "Winner7777" 
     }, 
     "chat": { 
      "id": 219633031, 
      "first_name": "Shreeeeeee", 
      "username": "Winner7777", 
      "type": "private" 
     }, 
     "date": 1472457375, 
     "text": "Aata aala" 
     } 
    }, 
    { 
     "update_id": 920493887, 
     "message": { 
     "message_id": 124, 
     "from": { 
      "id": 219633031, 
      "first_name": "Shreeeeeee", 
      "username": "Winner7777" 
     }, 
     "chat": { 
      "id": 219633031, 
      "first_name": "Shreeeeeee", 
      "username": "Winner7777", 
      "type": "private" 
     }, 
     "date": 1472457387, 
     "text": "Jeva tuzyakadun reply aala tevha" 
     } 
    }, 
    { 
     "update_id": 920493888, 
     "message": { 
     "message_id": 125, 
     "from": { 
      "id": 219633031, 
      "first_name": "Shreeeeeee", 
      "username": "Winner7777" 
     }, 
     "chat": { 
      "id": 219633031, 
      "first_name": "Shreeeeeee", 
      "username": "Winner7777", 
      "type": "private" 
     }, 
     "date": 1472457443, 
     "text": "Deposite" 
     } 
    }, 
    { 
     "update_id": 920493889, 
     "message": { 
     "message_id": 127, 
     "from": { 
      "id": 201520743, 
      "first_name": "Chandrakant", 
      "last_name": "Kumathekar", 
      "username": "chandrakant_k" 
     }, 
     "chat": { 
      "id": 201520743, 
      "first_name": "Chandrakant", 
      "last_name": "Kumathekar", 
      "username": "chandrakant_k", 
      "type": "private" 
     }, 
     "date": 1472457645, 
     "text": "\/menu", 
     "entities": [ 
      { 
      "type": "bot_command", 
      "offset": 0, 
      "length": 5 
      } 
     ] 
     } 
    }, 
    { 
     "update_id": 920493890, 
     "message": { 
     "message_id": 128, 
     "from": { 
      "id": 219633031, 
      "first_name": "Shreeeeeee", 
      "username": "Winner7777" 
     }, 
     "chat": { 
      "id": 219633031, 
      "first_name": "Shreeeeeee", 
      "username": "Winner7777", 
      "type": "private" 
     }, 
     "date": 1472457670, 
     "text": "\/menu", 
     "entities": [ 
      { 
      "type": "bot_command", 
      "offset": 0, 
      "length": 5 
      } 
     ] 
     } 
    }, 
    { 
     "update_id": 920493891, 
     "message": { 
     "message_id": 130, 
     "from": { 
      "id": 201520743, 
      "first_name": "Chandrakant", 
      "last_name": "Kumathekar", 
      "username": "chandrakant_k" 
     }, 
     "chat": { 
      "id": 201520743, 
      "first_name": "Chandrakant", 
      "last_name": "Kumathekar", 
      "username": "chandrakant_k", 
      "type": "private" 
     }, 
     "date": 1472457848, 
     "text": "Deposite" 
     } 
    }, 
    { 
     "update_id": 920493892, 
     "message": { 
     "message_id": 132, 
     "from": { 
      "id": 201520743, 
      "first_name": "Chandrakant", 
      "last_name": "Kumathekar", 
      "username": "chandrakant_k" 
     }, 
     "chat": { 
      "id": 201520743, 
      "first_name": "Chandrakant", 
      "last_name": "Kumathekar", 
      "username": "chandrakant_k", 
      "type": "private" 
     }, 
     "date": 1472457883, 
     "text": "Deposite" 
     } 
    }, 
    { 
     "update_id": 920493893, 
     "message": { 
     "message_id": 133, 
     "from": { 
      "id": 219633031, 
      "first_name": "Shreeeeeee", 
      "username": "Winner7777" 
     }, 
     "chat": { 
      "id": 219633031, 
      "first_name": "Shreeeeeee", 
      "username": "Winner7777", 
      "type": "private" 
     }, 
     "date": 1472468407, 
     "text": "\/menu", 
     "entities": [ 
      { 
      "type": "bot_command", 
      "offset": 0, 
      "length": 5 
      } 
     ] 
     } 
    }, 
    { 
     "update_id": 920493894, 
     "message": { 
     "message_id": 134, 
     "from": { 
      "id": 219633031, 
      "first_name": "Shreeeeeee", 
      "username": "Winner7777" 
     }, 
     "chat": { 
      "id": 219633031, 
      "first_name": "Shreeeeeee", 
      "username": "Winner7777", 
      "type": "private" 
     }, 
     "date": 1472473070, 
     "text": "\/menu", 
     "entities": [ 
      { 
      "type": "bot_command", 
      "offset": 0, 
      "length": 5 
      } 
     ] 
     } 
    } 
    ] 
}

我已生成使用newtonsoft json2csharp

public class From 
{ 
    public int id { get; set; } 
    public string first_name { get; set; } 
    public string last_name { get; set; } 
    public string username { get; set; } 
} 

public class Chat 
{ 
    public int id { get; set; } 
    public string first_name { get; set; } 
    public string last_name { get; set; } 
    public string type { get; set; } 
    public string username { get; set; } 
} 

public class Entity 
{ 
    public string type { get; set; } 
    public int offset { get; set; } 
    public int length { get; set; } 
} 

public class Message 
{ 
    public int message_id { get; set; } 
    public From from { get; set; } 
    public Chat chat { get; set; } 
    public int date { get; set; } 
    public string text { get; set; } 
    public List<Entity> entities { get; set; } 
} 

public class Result 
{ 
    public int update_id { get; set; } 
    public Message message { get; set; } 
} 

public class RootObject 
{ 
    public bool ok { get; set; } 
    public List<Result> result { get; set; } 
}

类反序列化

var d = Newtonsoft.Json.JsonConvert.DeserializeObject(rcvd_data);

下一步该做什么？如何把这一切工作？我很困惑，请帮忙。

来源

2016-08-30 ck jon

的所有属性，当您使用DeserializeObject指定类型，像这样：'消息消息= Newtonsoft.Json.JsonConvert.DeserializeObject （rcvd_data）;'。然后你可以检索消息属性（'message.text'）。 –

这个问题被问到500次，并没有显示研究工作！ –

[将JSON数据反序列化为使用JSON.NET的C＃]可能的重复（http://stackoverflow.com/questions/2546138/deserializing-json-data-to-c-sharp-using-json-net） –

要反序列化使用此代码：

RootObject ro = JsonConvert.DeserializeObject<RootObject>(rcvd_data);

而且在ro拥有所有数据。

例

bool ok = ro.ok; 

foreach(Result r in ro.result) 
{ 
    int uId = r.update_id; 
    Message m = r.message; 
    int msgId = m.message_id; 
}

来源

2016-08-30 08:40:01 BWA

感谢您的快速回复我做你所说的一切okk但我得到一些值为空，因为我编译它。我错过了什么？ –

你有什么值为空？我检查它 – BWA

结果结果= JsonConvert.DeserializeObject （rcvd_data）; int id = Result.update_id; –

尝试这种方式

var d = Newtonsoft.Json.JsonConvert.DeserializeObject<RootObject>(rcvd_‌data);

然后d将包含RootObject名单。通过使用foreach迭代就可以得到RootObject模型

来源

2016-08-30 08:48:42 Mostafiz

根据Json数据判断，它应该反序列化到'RootObject'类。从这个对象中，你可以访问一个'Message'对象列表。 –

是的第一次我犯了错误，但不幸的是，在编辑过程中，我的力量消失了，所以无法编辑，现在确定 – Mostafiz

string data = @"{""ok"":true,""result"":[{""update_id"":920493886,..."; 

RootObject ro = Newtonsoft.Json.JsonConvert.DeserializeObject<RootObject>(data); 

foreach (Result result in ro.result) 
{ 
     //two example fields 
     Console.WriteLine("update_id= " + result.update_id); 
     Console.WriteLine("message text= "+result.message.text); 
}

来源

2016-08-30 08:58:37 robor78

反序列化json数据c＃

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