我想从我的android应用程序发送一个字符串到服务器。该字符串包含:用户名,密码和以64为基础编码的图像。它们之间是空格(“”)。我正在使用heroku来存储服务器,并使用postgreSQL数据库。我有一个名为users
的表格,列表为:userid,password, encoded image
,它们都是格式文本。从Android发送一个字符串到一个Spring服务器
当我创建我给userid and the password
一个新的用户,列encodedimage是空的。我想在将图像上传到服务器并编辑encodedimage
列时更新表格。
这里是如何从我的android发送字符串:
request=Utils.name+" "+Utils.password;
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
image.compress(Bitmap.CompressFormat.JPEG, 100, byteArrayOutputStream);
request = request+ " " + Base64.encodeToString(byteArrayOutputStream.toByteArray(), Base64.DEFAULT);
try {
URL url = new URL(params[0]);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setReadTimeout(15000);
urlConnection.setConnectTimeout(15000);
urlConnection.setRequestMethod("POST");
urlConnection.setDoOutput(true);
urlConnection.setChunkedStreamingMode(0);
OutputStream outputStream = urlConnection.getOutputStream();
OutputStreamWriter outputStreamWriter = new OutputStreamWriter(outputStream, "UTF-8");
BufferedWriter bufferedWriter = new BufferedWriter(outputStreamWriter);
bufferedWriter.write(request);
bufferedWriter.flush();
bufferedWriter.close();
outputStreamWriter.close();
outputStream.close();
int response=urlConnection.getResponseCode();
urlConnection.disconnect();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
如果我从cmd
更新我的桌子它的工作原理,但是从码事实并非如此。
这里是我的控制器:
@Controller
public class UploadController implements Constant {
@RequestMapping(value = "/upload-image", method = RequestMethod.POST)
public void handleUploadImageRequest(@RequestBody String request) {
String[] details = request.split(" ");
String name = details[0];
String password = details[1];
byte[] decodedImage = Base64.getDecoder().decode(details[2]);
if (decodedImage.length > 0) {
try {
Image image = ImageIO.read(new ByteArrayInputStream(decodedImage));
Connection connection = null;
Statement statement = null;
String updateUSER = "UPDATE " + TABLE_USERS + " SET " + COLUMN_ENCODEDIMAGE + "='" + details[2]
+ "' WHERE " + COLUMN_USERID + "='" + name + "' AND '" + COLUMN_PASSWORD + "='" + password + "';";
try {
connection = DatabaseUtils.getConnection();
statement = connection.createStatement();
statement.executeUpdate(updateUSER);
statement.close();
connection.close();
} catch (SQLException e) {
e.printStackTrace();
}
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
在Heroku的日志中,我发现:
org.springframework.http.converter.HttpMessageNotReadableException:需要请求主体缺少的:public void com.rares。 controllers.UploadController.handleUploadImageRequest(java.lang.String)
android代码是否正常?问题在哪里,或者我该怎么做。请不要将我指向已弃用的方法。 我
但我知道如何与拆分获得控制器中的值(”“) – ProgIsMetal
你能和你的方法编辑我的控制器吗?我应该用请求参数来做吗?为什么要求身体现在不是有用的? – ProgIsMetal
如你所见,你不会再发送空格。所以不要在空间上分裂。 – greenapps