当我尝试打开“.EXE”文件与ReadFile()
的Windows API,它只是返回,如文件的2第一个字符:MZ
读出“二进制”与ReadFile的WinAPI的文件
这里是我的代码:
#define BUFFERSIZE 5000
VOID CALLBACK FileIOCompletionRoutine(
__in DWORD dwErrorCode,
__in DWORD dwNumberOfBytesTransfered,
__in LPOVERLAPPED lpOverlapped
);
VOID CALLBACK FileIOCompletionRoutine(
__in DWORD dwErrorCode,
__in DWORD dwNumberOfBytesTransfered,
__in LPOVERLAPPED lpOverlapped)
{
_tprintf(TEXT("Error code:\t%x\n"), dwErrorCode);
_tprintf(TEXT("Number of bytes:\t%x\n"), dwNumberOfBytesTransfered);
g_BytesTransferred = dwNumberOfBytesTransfered;
}
HANDLE hFile;
DWORD dwBytesRead = 0;
char ReadBuffer[BUFFERSIZE] = { 0 };
OVERLAPPED ol = { 0 };
hFile = CreateFile(fullFilePath.c_str(), // file to open
GENERIC_READ, // open for reading
FILE_SHARE_READ, // share for reading
NULL, // default security
OPEN_EXISTING, // existing file only
FILE_ATTRIBUTE_NORMAL | FILE_FLAG_OVERLAPPED, // normal file
NULL); // no attr. template
ReadFileEx(hFile, ReadBuffer, BUFFERSIZE - 1, &ol, FileIOCompletionRoutine);
当我打印ReadBuffer
这只是MZ
(exe文件)。
但使用:
std::ifstream file(argv[1], std::ios::in | std::ios::binary);
它的工作完美。 如何使用ReadFile读取二进制文件?
你怎么打印'ReadBuffer'?作为NUL终止的字符串,我怀疑。当然不是。 –
@IgorTandetnik我把'ReadBuffer'的值放到String中,并用'std :: cout'打印字符串。 –
准确地说。您将它打印为文本数据,但它是二进制数据。它可能在'MZ'后面有一个零字节,并且打印在那里停止。 –