2017-04-30 47 views
0

我正在一个类项目,我需要一个功能的形式。我试图让它工作,但每次我点击提交按钮时,它都会将我带到一个空白页面。我知道有什么不对,因为我在这个主题上发现了其他问题,但没有任何答案有帮助。因此,这里是我的本钱(删节凝结的东西):窗体去空白php

HTML:

Email address*:<br> <input type="text" name="email" required> 
    <br> 
    </fieldset> 
    <br> 
    <br> 
    <fieldset> 
     <legend>Room Information</legend> 
    Which room would you like us to reserve for you?<br> 
     <select name="Room"> 
     <option value="TeaRoom">The Tea Room</option> 
     <option value="CaptainsSuite">The Captain's Suite</option> 
     <option value="GreenRoom">The Green Room</option> 
     <option value="Valentine">The Valentine Suite</option> 
     <option value="Turkish">The Turkish Delight</option> 
     <option value="Music">The Music Room</option> 
     <option value="Bridal">The Bridal Suite</option> 
     <option value="GuestCottage">The Guest Cottage</option> 
     </select> 
     <br><br> 
    How many people are in your party?<br> 
     <input type="radio" name="number" value="1">1<br> 
     <input type="radio" name="number" value="2">2<br> 
     <input type="radio" name="number" value="3">3<br> 
     <input type="radio" name="number" value="4">4<br> 
    <br><br> 
    Date of Check In:<br> <input type="text" name="checkindate"><br> 
    <br> 
    Date of Check Out:<br><input type="text" name="checkoutdate"> 
    <br> 
    <br> 
    Do you, or anyone in your party, have any special dietary requirements?<br> 
    <textarea rows="4" cols="50" name="comment"> 
    </textarea> 
    <br> 
    </fieldset> 
    <br> 
    <br> 
     <input type="submit" value="Submit"> 

PHP:

<?php 
$field_name = $_POST['name']; 
$field_address = $ POST ['address']; 
$field_city = $ POST ['city']; 

$field_homephone = $ POST ['homephone']; 
$field_cellphone = $ POST ['cellphone']; 
$field_email = $_POST ['email']; 
$field_Room = $ POST ['Room']; 

$field_checkindate = $ POST ['checkindate']; 
$field_checkoutdate = $ POST ['checkoutdate']; 
$field_comment = $ POST ['comment']; 


$radio_button = $_POST['number']; 
$drop_down_item = $_POST['state']; 



$mail_to = '[email protected]'; 
$subject = 'Reservation '.$field_name; 

$body_message = 'From: '.$field_name."\n"; 
$body_message .= 'E-mail: '.$field_email."\n"; 
$body_message .= 'Message: '.$field_message; 

$headers = 'From: '.$field_email."\r\n"; 
$headers .= 'Reply-To: '.$field_email."\r\n"; 

$mail_status = mail($mail_to, $subject, $body_message, $headers); 

if ($mail_status) { ?> 
    <script language="javascript" type="text/javascript"> 
     alert('Thank you for the message. We will contact you shortly with your confirmation.'); 
     window.location = 'contactpage.html'; 
    </script> 
<?php 
} 
else { ?> 
    <script language="javascript" type="text/javascript"> 
     alert('Message failed. Please, send an email to [email protected]'); 
     window.location = 'contactpage.html'; 
    </script> 
<?php 
} 
?> 

编辑:我意识到这是一个重复的问题。我问这是因为我想知道我做错了什么,因为这个问题已被重复,而不是帮助我。

+0

您复制/粘贴您的PHP代码?如果是这样,用'$ _POST'替换所有**出现的'$ POST'。 – rickdenhaan

+0

让我给你介绍双引号。您可以将''From:'。$ field_name。“\ n”'更改为'“From:$ field_name \ n”'。这将产生更多可读的代码,而不需要连接。 – Manngo

+0

rickdenhaan,其中的一部分,是的,其中一部分是我自己输入的。处理代码的任何事情都是ADHD患者最糟糕的噩梦。 Geesh! Manngo,你必须原谅我,有时候我的摄取有点慢。当你说改变'From:等'中的单引号时到“From:等”这是否也意味着我改变单引号到这个东西的任何地方?就像我说的,我是新来的。 –

回答

0

您的$_POST错误您使用的是$ POST与空间。

$field_name = $_POST['name']; 
$field_address = $_POST ['address']; 
$field_city = $_POST ['city']; 

$field_homephone = $_POST ['homephone']; 
$field_cellphone = $_POST ['cellphone']; 
$field_email = $_POST ['email']; 
$field_Room = $_POST ['Room']; 

$field_checkindate = $_POST ['checkindate']; 
$field_checkoutdate = $_POST ['checkoutdate']; 
$field_comment = $_POST ['comment']; 


$radio_button = $_POST['number']; 
$drop_down_item = $_POST['state'];