我有四个字符串长度语句我想验证,但只有两个正在工作。字符串长度问题
$name = "mike";
$age = "54";
$city = "Chicago";
$building = "Madadnock";
$lengthOfString1 = strlen ($name);
echo "String length of 'name' " . $lengthOfString1 . "</br>";
$lengthOfString2 = strlen ($age);
echo "String length of 'age' " . $lengthOfString2 . "</br>";
$lengthOfString3 = strlen ($city);
echo "String length of 'city' " . $lengthOfstring3 . "</br>";
$lengthOfString4 = strlen ($building);
echo "String length of 'building' " . $lengthOfstring4 . "</br>";
前两位是唯一能够工作的人。任何帮助将是伟大的!在PHP
添加关于最后两条陈述不起作用的更多详细信息 – RomanPerekhrest
此问题应该与[PHP:“Notice:Undefined variable”,“Notice:Undefined index”和“Notice:Undefined offset”重复关闭] (http://stackoverflow.com/questions/4261133/php-notice-undefined-variable-notice-undefined-index-and-notice-undef) –
旁注:''不是一个有效的标记标记; '
'是。 –