在bash中分割字符串

Question

我想监视应用程序服务器中的一些挂起的线程，并且我得到了这一行。

[5/30/16 11:31:18:501 CDT] 00000655 ThreadMonitor W WSVR0606W: Thread "MessageListenerThreadPool : 38" (00000655) was previously reported to be hung but has completed. It was active for approximately 964450 milliseconds. There is/are 0 thread(s) in total in the server that still may be hung.

我需要在“There is/0 is thread（s）”中获得0。
我试图用cut来分割它，但一切都很糟糕。我也尝试使用分隔符，但字符串太长。
我该如何拆分它？

Answer 1

您可以使用sed捕捉号码之间 “有/是” 和 “线”，并删除一切，就像这样：

sed 's/.*There is\/are \([0-9]\+\) thread.*/\1/' file 

Answer 2

sed -nr 's/.*are ([0-9]+) thread.*/\1/p' file 

---

-r, --regexp-extended 
use extended regular expressions in the script. 

-n, --quiet, --silent 
suppress automatic printing of pattern space