1
我想构建一个简单的应用程序,它能够通过PHP界面从在线mysql数据库检索数据。但是当我试图检索JSON并使用gson解析本地Java对象时,我仍然收到下面的错误。我相信它与用于创建数组的PHP方法有关,因为这是我第一次进入PHP,所以如果有人能够看一看,这将是有帮助的。运行时Android到PHP到MySQL:预计BEGIN_ARRAY,但STRING在第1行1
错误:
10-10 17:51:30.146: W/System.err(683): Caused by: java.lang.IllegalStateException: Expected BEGIN_ARRAY but was STRING at line 1 column 1
PHP方法返回 '乔布斯' 的数组:
public function getAllJobs($email) {
$result = mysql_query("SELECT * from from job WHERE email = '$email'") or die(mysql_error());
$rows = array();
while (($r = mysql_fetch_array($result)) {
$rows[$r['jobId'][$r['desc']] = array(
'techId' => $r['techId'],
'email' => $r['email'],
'dateCreated' => $r['dateCreated'].
'dateClosed' => $r['dateClosed']
);
}
return $rows;
}
调用数据库功能类:
} else if ($tag == 'GetAll') {
$email = $_POST['email'];
$password = $_POST['password'];
$result = array();
$result = $db->getAllJobs($email);
echo json_encode($result);
}
招聘类应该从php/sql查询返回:
public class Job extends Message{
public Job(MessageType m)
{
this.messageType = m.toString();
}
public String messageType ;
public String jobId;
public String email;
public String techId;
public String desc;
public Date dateCreated;
public Date dateClosed;
@Override
public String getType() {
return messageType;
}
}
最后,从类CloudConnect Java代码:
public synchronized List<Message> getAll(Message m) throws IOException {
List<Message> mList = new ArrayList<Message>();
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost(site);
post.setEntity(new UrlEncodedFormEntity(validateMessage(m)));
HttpResponse response = client.execute(post);
StatusLine status = response.getStatusLine();
if (status.getStatusCode() == 200) {
HttpEntity entity = response.getEntity();
is = entity.getContent();
try {
Reader read = new InputStreamReader(is);
mList = Arrays.asList(gson.fromJson(read, Message[].class));
is.close();
} catch (Exception e) {
e.printStackTrace();
}
}
return mList;
}
你指的是阵列结果吗?或json_encode方法?我更新了代码以反映我认为正确的内容,但我对PHP或Json没有真正的了解。 – fakataha
为了帮助你,只需编辑你的问题与流的内容。如果你不知道该怎么做,请看这里例如:http://stackoverflow.com/a/309718/1360888 – giampaolo
这是最终帮助我解决问题。一些沿着你的建议,但不知道如何在Eclipse中显示输入。 String all = EntityUtils.toString(entity); Log.d(“response”,all);让我看到了PHP抛出的错误,最后是json格式,所以我可以验证它是我想要的。 – fakataha