2010-04-19 73 views
1

这个问题很容易修复客户端。但是为了提高性能,我想直接将其写入数据库。在一个查询中订购混合型混合mysql搜索结果?

LIST a 
+------+-------+-------+ 
| name | score | cre | 
+------+-------+-------+ 
| Abe | 3  | 1  | 
| Zoe | 5  | 2  | 
| Mye | 1  | 3  | 
| Joe | 3  | 4  | 

想要检索没有重复的加入混合结果。

Zoe (1st highest score) 
Joe (1st last submitted) 
Abe (2nd highest score) 
Mye (2nd last submitted) 
... 

客户端我自己采取每个搜索,并通过它们一步。 但在100.000+以上它变得尴尬。为了能够使用LIMIT功能将会使事情变得更加轻松!

SELECT name FROM a ORDER BY score DESC, cre DESC; 
SELECT name FROM a ORDER BY cre DESC, score DESC; 
+0

Hello Fredrik,你准确的需要你解释一下吗? – Karthik 2010-04-19 11:38:59

回答

1

MySQL不提供分析函数,如ROW_NUMBER

一种方式来实现,这将是两个查询不同Order By,连在一起的

Select s.name, s.score_num, c.cre_num 
From 
(
    Select name, @score_num := @score_num + 1 As score_num 
    From your_table, (SELECT @score_num := 0) v 
    Order By score Desc 
) s 
Join 
(
    Select name, @cre_num := @cre_num + 1 As cre_num 
    From your_table, (SELECT @cre_num := 0) v 
    Order By cre Desc 
) c 
On (c.name = s.name) 

回报

name score_num cre_num 
Joe   3  1 
Mye   4  2 
Zoe   1  3 
Abe   2  4 

这是你想要的吗?

+0

是的,非常好的解决方案!通过加入数据,我可以选择如何衡量其重要性。最佳的是我的情况实际上不是严格的版本,而是总结的版本。做得好! [...] SELECT [...](s.score_num Fredrik 2010-04-19 12:39:16