2012-10-20 136 views
0

我有以下的代码,明显的作品,但我相当肯定存在的CoffeeScript表达这种更简洁的方式:的CoffeeScript - 数组初始化

todos = [] 

    for i in [1..10]                    
    todos.push App.store.find App.Todo, i 

回答

1
todos = (App.store.find(App.Todo, i) for i in [1..10]) 

的圆括号表示list comprehension,这将返回值收集到数组中并返回。

考虑下面的两个例子。封闭的圆括号改变了Coffeescript解释循环的方式。

# With parentheses (list comprehension) 
todos = (App.store.find(App.Todo, i) for i in [1..10]) 

# Without parentheses (plain old loop) 
todos = App.store.find(App.Todo, i) for i in [1..10] 

和输出:

// With parentheses 
todos = (function() { 
    var _i, _results; 
    _results = []; 
    for (i = _i = 1; _i <= 10; i = ++_i) { 
    _results.push(App.store.find(App.Todo, i)); 
    } 
    return _results; 
})(); 

// Without parentheses 
for (i = _i = 1; _i <= 10; i = ++_i) { 
    todos = App.store.find(App.Todo, i); 
} 
+0

括号改变什么的CoffeeScript认为循环体是,它不在于是否将评估一个数组(考虑一下[这个循环(HTTP ://coffeescript.org/#try:f%20%3D%20-%3E%20c%20%3D%20b%20for%20b%20in%20a%0A)汇编成)。如果编译器检测到数组不会被使用(如[this循环](http://coffeescript.org/#try:f%20%3D%20-%3E%0A %20%20%20%20℃%20%3D%20B%20for%20B%20英寸%20A%0A%20%20%20%2011%0A))。 –

+0

聪明。谢谢你的澄清! –