2015-02-11 103 views

回答

2

假设A是输入的图像数据,这可能是一个办法 -

%// Initialize vectors for old and new pixels tuplets 
oldval = [140,50,61] 
newval = [150,57,80] 

%// Reshape the input array to a 2D array, so that each column would 
%// reprsent one pixel color information. 
B = reshape(permute(A,[3 1 2]),3,[]) 

%// Find out which columns match up with the oldval [3x1] values 
matches = all(bsxfun(@eq,B,oldval(:)),1) 
%// OR matches = matches = ismember(B',oldval(:)','rows') 

%// Replace all those columns with the replicated versions of oldval 
B(:,matches) = repmat(newval(:),1,sum(matches)) 

%// Reshape the 2D array back to the same size as input array 
out = reshape(permute(B,[3 2 1]),size(A)) 

采样运行 -

>> A 
A(:,:,1) = 
    140 140 140 
    40 140 140 
A(:,:,2) = 
    50 20 50 
    50 50 50 
A(:,:,3) = 
    61 65 61 
    61 61 61 
>> out 
out(:,:,1) = 
    150 140 150 
    40 150 150 
out(:,:,2) = 
    57 20 57 
    50 57 57 
out(:,:,3) = 
    80 65 80 
    61 80 80 
+0

你能告诉我怎么用替换'OLDVAL(:)'?旧的颜色是RGB(140,50,61) – Tak 2015-02-11 04:30:07

+1

@shepherd检查编辑? – Divakar 2015-02-11 04:30:35

+0

谢谢:)。是否可以写一些解释你写的代码行的注释? :) – Tak 2015-02-11 04:32:25

1

bsxfun是我会解决它的办法。但是,如果您不熟悉它,则可以从图像中提取每个通道,为每个通道使用三个逻辑模板,然后使用logical AND进行组合。做和会发现你的图像中的像素,寻找特定的RGB三重。

因此,我们相应地设置每个通道的输出并重构图像以产生输出。

因此,鉴于你的输入图像A,一个可以这样做:

red = A(:,:,1); green = A(:,:,2); blue = A(:,:,3); 
mred = red == 140; mgreen = green == 50; mblue = blue == 61; 
final_mask = mred & mgreen & mblue; 
red(final_mask) = 150; green(final_mask) = 57; blue(final_mask) = 80; 
out = cat(3, red, green, blue); 
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