0
我在这里的逻辑有点困难,它已经越来越晚了,说实话,我很难过。迭代通过时隙
我需要通过时隙循环。
var settings = {
startOfWeek:0, //0 = Sunday, 1 = Monday
timeSlotGap: 30,
minTime: "09:00:00",
maxTime: "17:30:00",
numSlots: 0
};
因此,我可以指定一个时隙的间隙,因此,如果我是通过时隙(具有30分钟的间隔)来迭代这将是:
09:00
09:30
10:00
10:30
目前我有以下内容:
$(document).ready(function() {
getNumSlots(settings.minTime, settings.maxTime, settings.timeSlotGap);
for(var i = 1; i<=settings.numSlots; i++){
//I have no idea what I'm doing here
$('#calendar').append("<p>Timeslot:" + i +"</p>");
}
});
var WeekNo = moment().week();
var CurrentDate = getCurrentDate();
var WeekDay = moment().weekday();
var settings = {
startOfWeek:0, //0 = Sunday, 1 = Monday
timeSlotGap: 60,
minTime: "09:00:00",
maxTime: "17:30:00",
numSlots: 0
};
if(settings.startOfWeek == 0){
WeekDay = WeekDay - 1;
}
function getNumSlots(minTime, maxTime, timeSlotGap){
var minTimeSplit = minTime.split(":");
var hourStart = new Date("01/01/1900 " + minTime).getHours();
var hourEnd = new Date("01/01/1900 " + maxTime).getHours();
var minStart = new Date("01/01/1900 " + minTime).getMinutes();
var minEnd = new Date("01/01/1900 " + maxTime).getMinutes();
var diffHour = hourEnd - hourStart;
var diffMins = minEnd - minStart;
var slots = ((diffHour * 60) + diffMins)/timeSlotGap;
settings.numSlots = slots;
}
如果是通过30/60分钟这不会是一个问题,但因为我可以指定时间段即,90分钟任何事情它使一个稍微难循环一样简单。
嗨jabclab,这不是我试图得到的时间段数。这是时间自己的时间价值,即9点30分,10点10分,10点30分等,如果不明确,则表示抱歉。 –
@Jezzabeanz我的错误:)将更新答案 – jabclab
啊,它是完美的。谢谢@ jabclab! –