将StringIO对象转换为Django ImageFile

Question

我试图从StringIO（或cStringIO，更具体地说）获取数据并将其转换为django.core.files.images.ImageFile。

但它不起作用。所有这一切，我的意思是它以多种方式失败，而谷歌已经让我失败了。

到目前为止我有：

pi = ProductImage(product=product) 
image = ImageFile(image_file) 
image.name = image_name # defined elsewhere 
pi.source_image.save(image_name, image) 
pi.save() 

我的堆栈跟踪是这样的：

File "dev.py", line 359, in process_csv_item 
    pi.source_image.save(image_name, image) 
File "C:\Python26\lib\site-packages\django\db\models\fields\files.py", line 92, in save 
    self.name = self.storage.save(name, content) 
File "C:\Python26\lib\site-packages\django\core\files\storage.py", line 48, in save 
    name = self._save(name, content) 
File "C:\Python26\lib\site-packages\django\core\files\storage.py", line 168, in _save 
    for chunk in content.chunks(): 
File "C:\Python26\lib\site-packages\django\core\files\base.py", line 65, in chunks 
    counter = self.size 
File "C:\Python26\lib\site-packages\django\core\files\base.py", line 39, in _get_size 
    elif os.path.exists(self.file.name): 
AttributeError: 'cStringIO.StringI' object has no attribute 'name' 

我在哪里可以看未来？

Answer 1

使用django.core.files.base.ContentFile（IMAGE_FILE）：

pi = ProductImage(product=product) 
pi.source_image.save(image_name, ContentFile(image_file.read())) 
pi.save()