无法跳出For循环到另一个For循环

Question

使用批处理脚本，我正在打破内部for循环，并在外部for循环进行序列，但它返回一个错误说：

The syntax of the command is incorrect 

它指的是我的：断点标签。请指教。谢谢。

for /l %%A in (1, 1, %NumRuns%) do (
echo Doing run %%A of %NumRuns% 

    for /l %%B in (1, 1, 3) do (
     ping 127.0.0.1 -n 2 > NUL 
     tasklist /FI "IMAGENAME eq Reel.exe" 2>NUL | find /I /N "Reel.exe">NUL 
     echo innerloop top 
    echo Error lvl is %ERRORLEVEL% 
    if NOT "%ERRORLEVEL%"=="0" (
     echo innerloop middle 
     goto:breakerpoint 
    ) 
    echo innerloop bottom 
) 
taskkill /F /IM "Reel.exe" 
:breakerpoint rem this is error line 

) 
:end 
echo end of run 

pause 

Answer 1

一个goto休息总是当前代码块和当前代码块是与第一个括号开头的完整块，你的情况，你把所有嵌套FOR一次。

为了避免这种情况，您需要使用子功能。

for /L %%A in (1, 1, %NumRuns%) do (
    echo Doing run %%A of %NumRuns% 
    call :innerLoop 
) 
exit /b 

:innerLoop 
for /L %%B in (1, 1, 10) do (
    echo InnerLoop %%B from outerLoop %%A 
    if %%B == 4 exit /b 
) 
exit /b