请检查两个回声及其输出。在两个地方,我传递相同的值,但是当我使用server_time_as_per_users_zone()函数时,它只是返回错误的信息。我如何从第一个回声中获得类似的正确输出?任何想法?php时区错误输出传递给另一个函数
function distance_finder($_d1,$_d2){
$d1= new DateTime($_d1);
$d2= new DateTime($_d2);
$interval= $d1->diff($d2);
$r = ($interval->days * 24) + $interval->h;
return $r;
}
function server_time_as_per_users_zone($users_zone){
$dateTime = new DateTime('now', new DateTimeZone($users_zone));
$date1 = $dateTime->format("d-m-y h:m:sa");
return $date1;
}
echo distance_finder("15-04-2017 01:33:26pm", server_time_as_per_users_zone('Asia/Dhaka')); //Output is: 17487
echo distance_finder("15-04-2017 01:33:26pm","16-04-2017 02:33:29pm"); //Output is: 25 which is correct