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我对此很新。我想使用PHP从页面中提取表格,并在修改所有锚点的HREF值后返回HTML。 下面是表:用DOMdocument和DOMXpath刮网页
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=windows-1255">
<link rel="stylesheet" type="text/css" href="../CssGraduateE.css">
<title></title>
</head>
<body>
<div>
<br>
<table class="main" cellspacing="0" cellpadding="0">
<tbody>
<tr>
<td>
<br><span class="MainHeader">Subjects in Faculty - Electrical Engineering</span><br><br>
<table cellpadding="2" cellspacing="0" border="1" width="100%">
<tbody>
<tr>
<td><span class="SecondHeader"> Subject Number</span></td>
<td><span class="SecondHeader">Subject Name</span></td>
<td><span class="SecondHeader">Points</span></td>
<td><span class="SecondHeader">Semesters</span></td>
<td>Subject Site</td>
</tr>
<tr>
<td><a href="../Subjects/?SUB=46001">46001</a> </td>
<td nowrap="">Engineering of Distributed Software Sys</td>
<td>3</td>
<td><br></td>
<td><a target="_newtab" href="http://www.thislinkisok.com/courses/046001">www</a></td>
</tr>
<tr>
<td><a href="../Subjects/?SUB=46002">46002</a> </td>
<td nowrap="">Design and Analysis of Algorithms</td>
<td>3</td>
<td>B<br></td>
<td> <br></td>
</tr>
</tbody>
</table>
</td>
</tr>
</tbody>
</table>
<br>
<table border="0">
<tbody>
<tr>
<td>Last Update on :</td>
<td>Wednesday ,9 April 2014</td>
<td></td>
</tr>
</tbody>
</table>
</div>
</body>
</html>
我知道怎么抢我想表: $查询= $ xpath->查询('//表[@类= “主”] //台1 ]'); 但我该如何循环所有以“../xxx”开头的链接并将它们修改为如下所示的内容:“www.mynewlink.com/xxx”? 最后,我想将提取的表格作为HTML返回。我如何使用原生DOMDocument和DOMXpath来做到这一点?
谢谢大家!
谢谢!有效! – wpdev
为什么我需要创建一个新的$ container DOMDocument?我不能这样做:$ table = $ xpath-> query('// table [@ class =“main”] // table [1]');返回$ dom-> saveHTML($ table-> item(0)); – wpdev
@ user3510841如果你不这样做,你只会得到表的内部内容,没有'
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