值正在存储在数据库中,但它不是我所期待的。我以前尝试过很多方法,但这种似乎可行,但文件名不存储,当我试图直接从数据库下载文件时,它下载一个.bin文件格式,它看起来像table_Name-column_Name.bin 。存储文件名是BLOB - ## B.图片没有正确存储在MySQL数据库里
我的形式
<form class="form-horizontal" method="post" action="productsValidate.php" name="myForm" enctype="multipart/form-data">
<fieldset>
<legend>Add Product</legend>
<div class="form-group">
<label for="Product_Name" class="col-lg-2 control-label">Product Name</label>
<div class="col-lg-10">
<input type="text" class="form-control" id="Product_Name" placeholder="Name" required="required" name="Product_Name">
</div>
</div>
<div class="form-group">
<label for="Size" class="col-lg-2 control-label">Size</label>
<div class="col-lg-10">
<input type="text" class="form-control" id="Size" placeholder="Size" required="required" name="Size">
</div>
</div>
<div class="form-group">
<label for="Color" class="col-lg-2 control-label">Color</label>
<div class="col-lg-10">
<input type="text" class="form-control" id="Color" placeholder="Size" required="required" name="Color">
</div>
</div>
<div class="form-group">
<label for="price" class="col-lg-2 control-label">Price</label>
<div class="col-lg-10">
<input type="number" class="form-control" id="price" placeholder="price" required="required" name="price">
</div>
</div>
<div class="form-group">
<label for="image" class="col-lg-2 control-label">Select Image</label>
<div class="col-lg-10">
<input type="file" name="image" id="image">
</div>
</div>
<div class="form-group">
<label for="categoryId" class="col-lg-2 control-label">Category Id</label>
<div class="col-lg-10">
<?php
//your connection to the db and query would go here
include "../include/settings.php";
$conn = new mysqli($host, $user, $pwd, $sql_db);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT distinct Category_Id FROM products";
$result = mysqli_query($conn, $sql);
?>
<select id="categoryId" name="categoryId">
<option value = ""></option>
<?php
while($row = mysqli_fetch_array($result)) {
echo '<option value='.$row['Category_Id'].'>'.$row['Category_Id'].'</option>';
}
?>
</select>
</div>
</div>
<div class="form-group">
<label for="description" class="col-lg-2 control-label">Description</label>
<div class="col-lg-10">
<textarea type="text" class="form-control" id="description" placeholder="Description" required="required" name="description" pattern="[\sA-Za-z]+"></textarea>
</div>
</div>
<div class="form-group">
<div class="col-lg-6 col-lg-offset-2">
<button type="submit" class="btn btn-primary">Add Product</button>
</div>
</div>
</fieldset>
</form>
我的表单验证
<?php
$name = $_POST["Product_Name"];
$size = $_POST["Size"];
$color = $_POST["Color"];
$price = $_POST["price"];
$image = addslashes($_FILES['image']['tmp_name']);
$image = file_get_contents($image);
$image = base64_encode($image);
$image=basename($_FILES["image"]["tmp_name"],".jpg");
$category = $_POST['categoryId'];
$description = $_POST['description'];
insertProduct($name, $size, $color, $price, $image, $category, $description);
function insertProduct($name, $size, $color, $price, $image, $category, $description){
require_once ("../include/settings.php"); // Load MySQL log in credentials
$conn = @mysqli_connect ($host,$user,$pwd,$sql_db); // Log in and use database
if ($conn) { // check is database is avialable for use
$query = "INSERT INTO products
(Product_Id, Product_Name, Size, Color, Price, Picture, Category_Id, Description)
VALUES ('', '$name', '$size', '$color', '$price', '$image', '$category', '$description')";
$result = mysqli_query ($conn, $query);
if ($result) { // check if query was successfully executed
echo 'Successfully Added';
} else {
echo 'Product could not be added';
}
mysqli_close ($conn); // Close the database connect
} else {
echo "<p>Unable to connect to our database for adding the product.</p>";
}
}
?>
将图片上传到服务器上的文件夹并将其路径存储在数据库中通常会更好。 – Qirel